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Nadya [2.5K]
3 years ago
8

This parallel circuit has three resistors R1-120 ohm; R2-45 ohm: R3=360

Physics
1 answer:
Nina [5.8K]3 years ago
5 0

Answer:

the answer is 30 Ohms. Not found in the options provided

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A woman climbs up a ladder in 1.37 s at 2.20 m/s. How tall is the ladder?
ArbitrLikvidat [17]

Answer:

The ladder is 3.014 m tall.

Explanation:

To solve this problem, we must use the following formula:

v = x/t

where v represents the woman’s velocity, x represents the distance she climbed (the height of the ladder), and t represents the time it took her to move this distance

If we plug in the values we are given for the problem, we get:

v = x/t

2.20 = x/1.37

To solve this equation for x (the height of the ladder), we must multiply both sides by 1.37. If we do this, we get:

x = (2.20 * 1.37)

x = 3.014 m

Therefore, the ladder is 3.014 m tall.

Hope this helps!

6 0
4 years ago
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According to principle of conservation of energy, the total momentum of a system of masses in any direction remains constant unl
Sergeu [11.5K]
The principle of conservation of energy states that energy can neither be created nor destroyed, but can be changed from one form to another. The law of inertia on the other hand states that a body remains at a state of rest or motion on a straight line unless compelled by an external force. So i think that the answer is B, which is FALSE because the question is more related to the law of inertia(Newtons first law) than to the law of conservation of energy. Hope i helped.  
6 0
3 years ago
Which Particle in an atom has a positive charge?
tester [92]

Answer:

Protons

Explanation:

3 0
3 years ago
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A block of mass m1 = 19.5 kg slides along a horizontal surface (with friction, μk = 0.35) a distance d = 2.6 m before striking a
worty [1.4K]

Answer:

19.5 m/s

87.8 m

Explanation:

The acceleration of block one is:

∑F = ma

-m₁gμ = m₁a

a = -gμ

a = -(9.8 m/s²) (0.22)

a = -2.16 m/s²

The velocity of block one just before the collision is:

v² = v₀² + 2aΔx

v² = (8.25 m/s)² + 2 (-2.16 m/s²) (2.3 m)

v = 7.63 m/s

Momentum is conserved, so the velocity of block two just after the collision is:

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

m₁u₁ = m₂v₂

(18.5 kg) (7.63 m/s) = (7.25 kg) v

v = 19.5 m/s

The acceleration of block two is also -2.16 m/s², so the distance is:

v² = v₀² + 2aΔx

(0 m/s)² = (19.5 m/s)² + 2 (-2.16 m/s²) Δx

Δx = 87.8 m

7 0
3 years ago
How does an airbag help protect a passenger in a car following a car accident?
Roman55 [17]

Answer: A

Explanation:

6 0
3 years ago
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