C- K4O8 and K2O4
K4O8/4 =KO2
K2O4/2 =KO2
1
ammonia: NH3 (one nitrogen)
bleach: NaOCl (zero nitrogen)
Answer:
40.03g/mole
Explanation:
Given parameters:
Mass = 42.10 g/mole and abundance = 93.50%
Mass = 8.30 g/mole and abundance = 6.200%
Mass = 50.40 g/mole and abundace = 0.3000%
Find;
Average atomic mass = ?
Solution:
Average atomic mass = sum (mass x abundance)
Average atomic mass = (
) + (
x 8.3) + (
)
= 39.36g/mole + 0.52g/mole + 0.15g/mole
= 40.03g/mole
Hola aquí va la respuesta!
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Average atomic mass of an element is a sum of the product of the isotope mass and its relative abundance.
For example: Chlorine has 2 isotopes with the following abundances
Cl(35): Atomic mass = 34.9688 amu; Abundance = 75.78%
Cl(37): Atomic mass = 36.9659 amu; Abundance = 24.22 %
Average atomic mass of Cl = 34.9688(0.7578) + 36.9659(0.2422) =
= 26.4993 + 8.9531 = 35.4524 amu
Thus, the term “ average atomic mass “ is a <u>weighted</u> average so it is calculated differently from a normal average