During a compression at a constant pressure of 290 Pa, the volume of an ideal gas decreases from 0.62 m3 to 0.21 m3. The initial
1 answer:
You might be interested in
Answer:
The heat flows into the gas during this two-step process is 120 cal.
Explanation:
Given that,
Number of moles = 3
Heat capacity at constant volume = 4.9 cal/mol.K
Heat capacity at constant pressure = 6.9 cal/mol.K
Initial temperature = 300 K
Final temperature = 320 K
We need to calculate the heat flow in to gas at constant pressure
Using formula of heat
Put the value into the formula
We need to calculate the heat flow in to gas at constant volume
Using formula of heat
Put the value into the formula
We need to calculate the heat flows into the gas during two steps
Using formula of total heat
Hence, The heat flows into the gas during this two-step process is 120 cal.
Answer: 4.5 V
Explanation:
Given
The voltage of each cell is 1.5 V
If they are connected end to end their potential added to give a higher potential i.e. 1.5+1.5+1.5=4.5 V
