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aev [14]
3 years ago
7

Sodium chloride is produced from its elements

Chemistry
1 answer:
Kisachek [45]3 years ago
6 0

Answer:

                     Mass of Sodium  =  574.75 g

                     Mass of Chlorine  =  886.25 g

Explanation:

                   The  balance chemical equation for the synthesis of NaCl is,

                                        2 Na + Cl₂ → 2 NaCl

Step 1: <u>Find out moles of each reactant required,</u>

According to balance chemical equation,

                 2 moles of NaCl is produced by  =  2 moles of Na

So,

         25 moles of NaCl will be produced by  =  X moles of Na

Solving for X,

                     X  =  25 mol × 2 mol /  2 mol

                     X  =  25 moles of Na

Similarly for Cl₂,

According to balance chemical equation,

                 2 moles of NaCl is produced by  =  1 mole of Cl₂

So,

         25 moles of NaCl will be produced by  =  X moles of Cl₂

Solving for X,

                     X  =  25 mol × 1 mol /  2 mol

                     X  =  12.5 moles of Cl₂

Step 2: <u>Convert each moles to mass as;</u>

Mass  =  Moles × Atomic Mass

For Na,

Mass  =  25 mol × 22.99 g/mol

Mass  =  574.75 g

For Cl₂,

Mass  =  12.5 mol × 70.90 g/mol

Mass  =  886.25 g

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Answer:

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Explanation:

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3 years ago
154 pm is greater than 7.7 x10^-9<br> A. True<br> B. False
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The answer is false.
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A 50.0 mL solution of 0.141 M KOH is titrated with 0.282 M HCl . Calculate the pH of the solution after the addition of each of
Kobotan [32]

Answer:

pH =1 2.84

Explanation:

First we have to start with the <u>reaction</u> between HCl and KOH:

HCl~+~KOH->~H_2O~+~KCl

Now <u>for example, we can use a volume of 10 mL of HCl</u>. So, we can calculate the moles using the <u>molarity equation</u>:

M=\frac{mol}{L}

We know that 10mL=0.01L and we have the concentration of the HCl 0.282M, when we plug the values into the equation we got:

0.282M=\frac{mol}{0.01L}

mol=0.282*0.01

mol=0.00282

We can do the same for the KOH values (50mL=0.05L and 0.141M).

0.141M=\frac{mol}{0.05L}

mol=0.141*0.05

mol=0.00705

So, we have so far <u>0.00282 mol of HCl</u> and <u>0.00705 mol of KOH</u>. If we check the reaction we have a <u>molar ratio 1:1</u>, therefore if we have 0.00282 mol of HCl we will need 0.00282 mol of KOH, so we will have an <u>excess of KOH</u>. This excess can be calculated if we <u>substract</u> the amount of moles:

0.00705-0.00282=0.00423mol~of~KOH

Now, if we want to calculate the pH value we will need a <u>concentration</u>, in this case KOH is in excess, so we have to calculate the <u>concentration of KOH</u>. For this, we already have the moles of KOH that remains left, now we need the <u>total volume</u>:

Total~volume=50mL+10mL=60mL

60mL=0.06L

Now we can calculate the concentration:

M=\frac{0.00423mol}{0.06L}

M=0.0705

Now, we can <u>calculate the pOH</u> (to calculate the pH), so:

pOH=-Log(0.0705)

pOH=1.15

Now we can <u>calculate the pH value</u>:

14=~pH~+~pOH

pH=14-1.15=12.84

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Answer:

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Explanation:

During oxidative phosphorylation, the electrons from NADH and FADH₂ are combined with O₂ and the energy released in the process is used to synthesize ATP from ADP.

The components of the electron transport chain are located in the internal part of the mitochondrial membrane in eukaryotic cells, and in the cell membrane in bacteria. The transporters in the electron transport chain are organized into four complexes in the inner mitochondrial membrane. A fifth complex then couples these reactions to the ATP synthesis.

Complex II receives the electrons from the succinate, which is an intermediary in the Krebs cycle. These electrons are transferred to the FADH₂ and then to the Q coenzyme. This liposoluble molecule will transport the electrons from Complex II to Complex III. In this complex, the electrons are transferred from the <em>b</em> cytochrome to the <em>c</em> cytochrome. This <em>c </em>cytochrome, which is a peripheric membrane protein located in the external part of the inner membrane, then transports the electrons to Complex IV where finally they are transferred to the oxygen.

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weeeeeb [17]

Answer:

D. It contains a phosphate with higher phosphoryl transfer potential than ATP

Explanation:

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