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lubasha [3.4K]
3 years ago
14

What is the energy of a single photon of infrared light with a wavelength of 1.00 µm? 1 µm = 10^-6m

Physics
1 answer:
notka56 [123]3 years ago
3 0

Answer:

Energy is found as:

E = 1.987·10⁻¹⁹ J

Explanation:

Energy of a single photon of infrared light can be found by using the following formula:

E=hf

where

E = in Joules

h = Planck's constant = 6.627×10 ⁻³⁴ J

f = frequency in hertz

It can also be written as:

E = \frac{hc}{\lambda}

where

c = 2.998×10⁸ ms⁻¹

λ = wavelength

Wavelength is given in the question which is:

λ = 1×10⁻⁶m

Substitute all the values in the Energy formula

E = \frac{hc}{\lambda}\\E = \frac{(6.627\cdot10^{-34})(2.998\cdot10^8)}{1\cdot10^{-6}}\\E = 1.987\cdot10^{-19}J

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What is an accurate definition of a heat engine? A. a system that converts mechanical energy into thermal energy B. a system tha
Verizon [17]

Answer:

C

Explanation:

C. a system that converts thermal energy into other useful forms of energy

5 0
3 years ago
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How many times does a human heart beat during a person’s lifetime? How many gallons of blood does it pump? (Estimate that the he
Nostrana [21]

Answer: The heart pumps 124.2 billion cm³ of blood in a lifetime

Explanation:

as an adult the pulse rate average must be around 72 beats per minute.

The heart beats about 103,680 times in a day.

There are 365 days in a year

number of heart beat in a year = 365 days x 103,680 = 37,843,200 beats in a year

For every the heart pumps 50cm³ of blood,

Hence,

Amount of blood pump in a year = 50 x 37,843,200 = 1,892,160,000cm³ of blood pumped in a year.

Using the estimated lifespan average an individual is 69 years

So in a life time,

The human heart pumps = 1,892,160,000 x 69 years = 124,200,000,000

If the heart pumps 50cm³ of blood per beat, the heart pumps a total of 130,559,040,000 cm³ (130.6 billion cm³) of blood in a LIFETIME.

3 0
3 years ago
Two identical cars A and B are at rest on a loading dock with brakes released. Car C, of a slightly different style but of the s
Nadusha1986 [10]

Answer:

Explanation:

Let the velocity after first collision be v₁ and v₂ of car A and B . car A will bounce back .

velocity of approach = 1.5 - 0 = 1.5

velocity of separation = v₁ + v₂

coefficient of restitution = velocity of separation / velocity of approach

.8 = v₁ + v₂ / 1.5

v₁ + v₂ = 1.2

applying law of conservation of momentum

m x 1.5 + 0 = mv₂ - mv₁

1.5 = v₂ - v₁

adding two equation

2 v ₂= 2.7

v₂ = 1.35 m /s

v₁ = - .15 m / s

During second collision , B will collide with stationary A . Same process will apply in this case also. Let velocity of B and A after collision be v₃ and v₄.

For second collision ,

coefficient of restitution = velocity of separation / velocity of approach

.5 = v₃ + v₄ / 1.35

v₃ + v₄ = .675

applying law of conservation of momentum

m x 1.35 + 0 = mv₄ - mv₃

1.35 = v₄ - v₃

adding two equation

2 v ₄= 2.025

v₄ = 1.0125 m /s

v₃ = - 0 .3375  m / s

3 0
3 years ago
Round the number 14.587020 to 4 significant digits.
PilotLPTM [1.2K]
A. 14.59 is correctly rounded to 4 significant digits.
4 0
3 years ago
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A 1100 kg sports car accelerates from 0m/s to 32m/s in 10 seconds. What is the average power of the engine?
timurjin [86]

Answer:

The average power of the engine of the sports car is 56.32 kW

Explanation:

Given;

mass of the sports car, m = 1100 kg

initial velocity of the sports car, u = 0 m/s

final velocity of the sports car, v = 32 m/s

time of motion, t = 10 s

The kinetic energy of the car is given by;

K.E = ¹/₂m(v² - u²)

K.E = ¹/₂mv²

K.E = ¹/₂ x 1100 x 32²

K.E = 563200 J

The average power of the engine of the sports car is given by;

Pavg = Energy / time

Pavg = 563200 / 10

Pavg = 56320 W

Pavg = 56.32 kW

Therefore, the average power of the engine of the sports car is 56.32 kW

8 0
3 years ago
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