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NISA [10]
3 years ago
9

Asteroids are between 1000 km and less than 10 m in diameter. What is the diameter of most asteroids?

Physics
1 answer:
e-lub [12.9K]3 years ago
7 0

This question needs research to be answered. From the given information alone it can't be answered without making wild assumptions.

Ideally, you need to take a look at a distribution (or a histogram) of asteroid diameters, identify the "mode" of such a distribution, and find the corresponding diameter. That value will be the answer.

I am attaching one such histogram on asteroid diameters from the IRAS asteroid catalog I could find online. (In order to get a single histogram, you need to add the individual curves in the figure first). Eyeballing this sample, I'd say the mode is somewhere around 10km, so the answer would be: the diameter of most asteroid from the IRAS asteroid catalog is about 10km.

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Mariulka [41]

Answer: 0.4 Amps

Explanation:

Voltage of battery = 24 Volts

Current I = ?

Resistance of searchlight (R)= 60ohms (Ω is the symbol for ohms)

Then, apply the formula for ohms law

Voltage = Current x resistance

i.e V = I x R

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I = 24V / 60Ω

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3 years ago
A 4.3 kg steel ball and 6.5 m cord of negligible mass make up a simple pendulum that can pivot without friction about the point
Alekssandra [29.7K]

Answer

given,

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length of the chord, L = 6.5 m

mass of the block, m = 4.3 Kg

coefficient of friction, μ = 0.9

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here the potential energy of the bob is converted into kinetic energy

m g L = \dfrac{1}{2} mv^2

v= \sqrt{2gL}

v= \sqrt{2\times 9.8\times 6.5}

      v = 11.29 m/s

As the collision is elastic the velocity of the block is same as that of bob.

now,

work done by the friction force = kinetic energy of the block

f . d = \dfrac{1}{2} mv^2

\mu m g. d = \dfrac{1}{2} mv^2

d=\dfrac{v^2}{2\mu g}

d=\dfrac{11.29^2}{2\times 0.9 \times 9.8}

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the distance traveled by the block will be equal to 7.23 m.

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3 years ago
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nika2105 [10]
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Dennis_Churaev [7]

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How far away is Earth away from the sun?
alexira [117]
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Hope that helped :)
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3 years ago
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