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Gemiola [76]
3 years ago
6

A distance of 200 ft must be taped in a manner to ensure a standard deviation smaller than ± 0.04 ft. What must be the standard

deviation per 100 ft tape length to achieve the desired precision?Express your answer to three significant figures and include appropriate units.
Physics
1 answer:
Nutka1998 [239]3 years ago
3 0

Answer:

The error in tapping is ±0.02828 ft.

Explanation:

Given that,

Distance = 200 ft

Standard deviation = ±0.04 ft

Length = 100 ft

We need to calculate the number of observation

Using formula of number of observation

n=\dfrac{\text{total distance}}{\text{deviation per tape length}}

Put the value into the formula

n=\dfrac{200}{100}

n=2

We need to calculate the error in tapping

Using formula of error

E_{series}=\pm E\sqrt{n}

E=\dfrac{E_{series}}{\sqrt{n}}

Put the value into the formula

E=\dfrac{0.04}{\sqrt{2}}

E=\pm 0.02828\ ft

Hence, The error in tapping is ±0.02828 ft.

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The watermark can be of different types depending on the application. A watermark will resist manipulations of the media. Howeve
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<em>The first blank is </em><em>robust watermark</em>; a robust watermark will not resist tampering.

<em>The second blank is </em><em>fragile watermark</em><em>;</em> a fragile watermark will resist manipulations of the media.

<h3>What is a watermark?</h3>

A watermark is a faint design made in paper during manufacture that is visible when held against the light and clearly identifies the maker.

The watermark can be of different types depending on the application and they include:

  • A robust watermark will not resist tampering.
  • A fragile watermark will resist manipulations of the media.

Thus, The first blank is robust watermark; a robust watermark will not resist tampering.

The second blank is fragile watermark; a fragile watermark will resist manipulations of the media.

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You repeated a measurement 6 times and recorded the time using a stop watch: 5.8s, 4.6s, 4.8s, 5.1s, 4.3s, 4.6s. What average va
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Answer and Explanation

Arranging the measured values in increasing order;

4.3s, 4.6s, 4.6s, 4.8s, 5.1s, 5.8s

The two outliers are obviously 4.3s and 5.8s; An outlier is a value in a statistical sample which does not fit a pattern that describes most other data point. Outliers make the average value complicated. So, it is usually better for data to be precise with data points spreading out around a small area.

So, the mean is the average of the four remaining data points after removing the outliers.

Mean = (4.6 + 4.6 + 4.8 + 5.1)/4

Mean = 4.775s

So, the value recorded should be 4.775s, 4.78s or 4.8s depending on the number of decimal places allowed.

QED!

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What units must the constant G have in order for the u it’s F to be newtons (N)?
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The units for G must be [N][m^2][kg^{-2}]

Explanation:

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F=G\frac{m_1 m_2}{r^2}

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F is the force

G is the gravitational constant

m_1, m_2 are the masses of the two objects

r is the separation between the objects

We know that:

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  • The units of m_1,m_2 are kilograms (kg)
  • The units of r are metres (m)

So, we can rewrite the equation in terms of G, to find its units:

G=\frac{Fr^2}{m_1 m_2}=\frac{[N][m]^2}{[kg][kg]}=[N][m^2][kg^{-2}]

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