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Karolina [17]
3 years ago
13

How does an atom of bromine-79 become a bromide ion with a -1 charge?

Physics
1 answer:
Tanzania [10]3 years ago
3 0

a the atom loses 1 proton to have a total of 34

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Calculate the magnitude of the angular momentum of the earth due its daily rotation about its own axis
ioda
L=Iw
I_{earth} =  \frac{2}{5} r^{2}m= \frac{2}{5} (6371000^2m)(5.97*10^{24}kg)=9.71*10^ {37}
L_{earth}=Iw=(9.71*10^ {37})(7.27*10^{-5})=7.07*10^{33}<span>[/tex]</span>

7 0
3 years ago
A granite monument has a volume of 25,365.4 cm3. The density of granite is 2.7 g/cm3. Use this information to calculate the mass
Nana76 [90]
V = 25,364.4 cm^3   Is volumer = 2.7g/cm^3      Is density
To calculate mass you use formula:m= V*rTo avoid remembering this formula you can see the type of unit on each given variable. We can see that we have g/cm^3 and cm^3. If we multiply them, we negate cm^3 and cm^3 and we are left with g which is unit for mass.
the answer is :
m = 68,486,6 g   
6 0
3 years ago
A car of mass 1800 kg can be just be lifted. What is the least force that the electromagnet must use to lift the car? (1 g = 10
Doss [256]

Answer:

<h2>f=a×m</h2>

m=1800kg

1800000g×10N/kg

18000000N force is required to life the car

8 0
3 years ago
Which statement correctly describes the relationship between frequency and wavelength?
liraira [26]

For a wave:

v = fλ

v is the velocity, f is the frequency, and λ is the wavelength.

Assuming the velocity of the wave doesn't change...

If you increase its frequency, its wavelength will shorten.

5 0
3 years ago
Read 2 more answers
A 100-W lightbulb is placed in a cylinder equipped with a moveable piston. The lightbulb is turned on for 0.010 hour, and the as
Taya2010 [7]

Answer:

w =  - 508.53 joules

q = - 3091.47 joules

Explanation:

Let us convert the time in hours into seconds

0.010* 3600\\= 36

Change in internal energy

\delta E = p * \delta t

where E is the internal energy in Joules

p is the power in watts

and t is the time in seconds

\delta E = - 100 * 36\\

\delta E = - 3600 Joules

Amount of work done by the system

w = - P * \delta V

where P is the pressure and V is the volume

Substituting the given values in above equation, we get -

w = - 1 * ( 5.92 -0.90)\\

w = -5.02 liter-atmospheres

Work done in Joules

- 5.02 * 101.3\\= 508.53Joules

q = \delta E - w\\

Substituting the given values we get -

q = - 3600 - (-508.53)\\q = - 3091.47

Thus

w =  - 508.53 joules

q = - 3091.47 joules

7 0
3 years ago
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