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goldfiish [28.3K]
3 years ago
10

Gravity is measured using?

Physics
1 answer:
vlada-n [284]3 years ago
4 0
Gravity is measured with an instrument called a Gravimeter. Gravity is expressed using a special unit called a Newton. Although both of these answers would be technically correct, I believe the answer to this question is Newtons.
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Acceleration due to gravity on the moon is 1.6m/s^2 or about 16% of the value of gg on Earth. If an astronaut on the moon threw
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To solve this problem it is necessary to apply the concepts related to the conservation of Energy. Mathematically the conservation of kinetic energy must be paid in the increase of potential energy or vice versa. This expressed in algebraic terms is equivalent to

Kinetic Energy = Potential Energy

\frac{1}{2}mv^2 = mgh

Where

m = Mass

v = Velocity

g = Gravity

h = Height

As the mass is the same then we have to

\frac{1}{2} v^2 = gh

Rearrange to find v,

v = \sqrt{2gh}

Our values are given as

g = 1.6m/s^2

h = 7.8m

Therefore replacing we have

v = \sqrt{2(1.6)(7.8)}

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The only direct affectation is that concerning the Resistance or drag force generated by a fluid - such as air in the ground - that can diminish / sharpen the direct effects of gravity. Disregarding the resistance of the air, as we can see in the equation previously given, there should be no affectation because the speed depends on the gravity and height.

5 0
4 years ago
All of the following are good tips for controlling your emotions EXCEPT:
TEA [102]

Answer:

B

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Building up emotions can be bad for your health and hurt you mentally all other options are good.

8 0
4 years ago
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When the sphere makes a complete revolution around its circular path, does it spend:_______
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Answer:

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3 years ago
A man with a mass of 65.0 kg skis down a frictionless hill that is 5.00 m high. At the bottom of the hill the terrain levels out
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Answer:

The horizontal distance is 4.823 m

Solution:

As per the question:

Mass of man, m = 65.0 kg

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Height of ledge, h = 2 m

Now,

To calculate the horizontal distance from the edge of the ledge:

Making use of the principle of conservation of energy both at the top and bottom of the hill (frictionless), the total mechanical energy will remain conserved.

Now,

KE_{initial} + PE_{initial} = KE_{final} + PE_{final}

where

KE = Kinetic energy

PE = Potential energy

Initially, the man starts, form rest thus the velocity at start will be zero and hence the initial Kinetic energy will also be zero.

Also, the initial potential energy will be converted into the kinetic energy thus the final potential energy will be zero.

Therefore,

0 + mgH = \frac{1}{2}mv^{2} + 0

2gH = v^{2}

v = \sqrt{2\times 9.8\times 5} = 9.89\ m/s

where

v = velocity at the hill's bottom

Now,

Making use of the principle of conservation of momentum in order to calculate the velocity after the inclusion, v' of the backpack:

mv = (m + m')v'

65.0\times 9.89 = (65.0 + 20.0)v'

v' = 7.56\ m/s

Now, time taken for the fall:

h = \frac{1}{2}gt^{2}

t = \sqrt{\frac{2h}{g}}

t = \sqrt{\frac{2\times 2}{9.8} = 0.638\ s

Now, the horizontal distance is given by:

x = v't = 7.56\times 0.638 = 4.823\ m

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Hope this helps!

-Lilly

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3 years ago
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