The given question is incomplete. The complete question is as follows.
If more sugar were added to the solution on the left side of the tube, what would happen to the water level on the right side of the tube?
- There is more solute in the left arm of the tube than in the right arm of the tube.
- There is less free water in the right arm of the tube than in the left arm of the tube.
- Water is tightly clustered around the hydrophilic solute molecules on both sides of the membrane.
- Solutes can pass through the selectively permeable membrane from right to left, but free water cannot.
Explanation:
It is known that when water is able to diffuse through a semi-permeable membrane from a region of high water concentration to low water concentration is called osmosis.
Since, more amount of solute is present on the right side of the tube so, there will be less amount of free water present over there as compared to the left side of the tube.
Also, water will be clustered around the hydrophilic solute molecules which is present on both sides of the membrane.
Thus, we can conclude that the true statements are as follows.
- There is less free water in the right arm of the tube than in the left arm of the tube.
- Water is tightly clustered around the hydrophilic solute molecules on both sides of the membrane.
The signs of ΔS° and ΔH° will be negative.
A combustion reaction is a reaction in which a substance reacts with oxygen gas, releasing energy in the form of light and heat.
Combustion reactions must involve O2 as one reactant.
Consider the combustion of butane gas:
C₄H₁₀(g ) + 13/2O₂(g) → 4CO₂(g) + 5H₂O(g)
4 + 13/2 4 + 5
10.5 mol -------------> 9 mol
As the number of moles decreases entropy will decrease
so ΔS° = negative
since this example for combustion reaction heat is released (exothermic)
so ΔH° = negative.
Learn more about ΔS° here:
brainly.com/question/3784176
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Explanation:
96.485 columbs=1 faraday will
deposit 64/2g= 32 g cu ion
therfore it will require
96,485 ×2/32 =? coulombs or 1/16 of
Faraday= 1 / 16 mole of electrons .
Answer: 159 grams
Explanation:
Copper (ii) oxide has the chemical formula CuO.
Now given that:
Mass of CuO in grams = ? (let unknown value be Z)
Number of moles = 2.00 moles
Molar mass of CuO = ?
For the molar mass of CuO: Atomic mass of Copper = 63.5g ; Oxygen = 16g
= 63.5g + 16g
= 79.5 g/mol
Apply the formula:
Number of molecules = (mass in grams/molar mass)
2.00 moles = (Z / 79.5 g/mol)
Z = 79.5 g/mol x 2.00 moles
Z = 159g
Thus, there are 159 grams in 2.00 moles of copper (ii) oxide