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Sliva [168]
3 years ago
8

What is the chemical equation for the boiling of Coca Cola to determine sugar content

Chemistry
1 answer:
yKpoI14uk [10]3 years ago
5 0
Your best guess for the boiling point of any version of Coke would be 100 C, the boiling point of water.

Diet Coke is mostly water (the flavourings are a very small amount relative to the amount of water). The largest ingredient will be the sweetener but there will be only a fraction of a gram of that. It is unlikely you will notice any deviation from the properties of water.

Standard Coke has quite a lot of sugar in it. A standard can (~300ml) contains about 40g of sugar. To put it another way, the contents are more than 10% sugar by weight and the solution is about 1/3 mol/L of sucrose (other sugars will be slightly different). A standard calculation using the ebullioscopic constant for water suggests the elevation of the boiling point will be barely 0.2 C, so small you'd struggle to measure it without good instruments and a good experimental setup.
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NA=72.264x1023

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What element is primarily used in appliances to make electronic chips
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Adding O2 to the reaction 6CO2 + 6H2O <---> C6H12O6 + 6O2, WHICH WAY WILL THE REACTION SHIFT?
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Increase in Oxygen shift the equilibrium towards reactant side.

<u>Explanation:</u>

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Types of osmosis...in 50 words​
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<h3>Types of Osmosis</h3>

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3 years ago
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Calculate the standard molar enthalpy for the complete combustion of liquid ethanol (C2H5OH) using the standard enthalpies of fo
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Answer:

Explanation:

For the reaction

C2H5OH (l) + 3 O2(g) = 2CO2(g) + 3 H2O

We can calculate the  standard molar enthalpy of combustion using the standard enthalpies of formation of the species involved in the reaction according to Hess law:

ΔHºc =  2ΔHºf CO2 (g) + 3ΔHºfH2O(l)  - ( ΔHºf C2H5OH (l) - 3ΔHºfO2 (g) )

( we were not give the water state but we know we are at standard conditions so it is in its liquid state )

The ΔHºfs can be found in appropiate reference or texts.

ΔHºc =  2ΔHºf CO2 (g)+ 3ΔHºfH2O(l)  - (  ΔHºf C2H5OH (l) -+3ΔHºfO2 (g) )

= [ 2 ( -393.52 ) + 3 ( -285.83 ) ] - [(  -276.2 + 0 ) ] kJ

ΔHºc =  -1368.33 kJ

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3 years ago
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