The density of aluminium is 2.70g/cm^3 . If a cube of aluminum weights 13.5 grams, what is the lengths of the edge of the cube.
1 answer:
Answer: -
1.71 cm
Explanation: -
Density of aluminium = 2.70 g /
Mass of aluminium = 13.5 g
We know density of a substance is the mass of the substance per unit volume.
Density = Mass / volume
Volume = Mass / density
Volume of aluminium = Mass of aluminium / Density of Aluminium
= 13.5 g / 2.70 g/
= 5
We know for a cube volume =
Length of the cube =
=
=1.71 cm
Thus if the density of aluminium is 2.70g/
and the cube of aluminum weights 13.5 grams, 1.71 cm is the length of the edge of the cube
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Answer:
<u>∆H° reaction = -890.3 kJ</u>
Explanation:
The given equation is :
Now ,
O2 is in the standard state so its ∆H° is zero.
∆H° is calculated by considering the formation of CO2 , H2O and CH4 .
..........∆H°a = -393.5 kJ
.....∆H°b = -285.8 kJ
..........∆H°c = -74.8 kJ
Multiply equation of water H2O by 2
and reverse the direction of equation of CH4
Hence the sign of ∆H°c = +74.8 kJ becomes +ve.
We are doing this because CH4 is to be in the reactant side not in the product side.
∆H° reaction = ∆H°a +2(∆H°b) -∆H°c
∆H° reaction = -393.5 - 2(285.8) + 74.8
∆H° reaction = -890.3 kJ
1 tablespoon = 0.5 ounces
We are required to find for 2 table spoons.
2 table spoons = 2 x 0.5 = 1 ounce.
Each bottle has 16 ounce.
Number of bottles = 4
So total number = 4 x 16 = 64 ounces.
Number of 2 table spoons =
= 64
Thus there are 64 2-tablespoon doses are in 4 bottles of medication containing 16 ounces each.