The molecular formula :
C₆H₁₄O₃PF
<h3>Further explanation</h3>
Given
39.10% carbon, 7.67% hydrogen, 26.11% oxygen, 16.82% phosphorus, and 10.30% fluorine.
Required
The molecular formula
Solution
mol ratio :
C = 39.1 : 12 = 3.258
H = 7.67 : 1 = 7.67
O = 26.11 : 16 = 1.632
P = 16.82 : 31 = 0.543
F = 10.3 : 19 = 0.542
Divide by 0.542
C = 6
H : 14
O = 3
P = 1
F = 1
The empirical formula :
C₆H₁₄O₃PF
(The empirical formula)n = the molecular formula
(C₆H₁₄O₃PF)=184.1
(6.12+14.1+3.16+31+19)n=184.1
(184)n=184.1
n = 1
Homogeneous mixture because it contains the same properties as homogeneous
Answer:
Original: P₁ = 710 mmHg, V₁ = 14.8 mL, T₁ = (273.2 + 11.0) K = 284.2 K
New: P₂ = 370 mmHg, V₂ = ? mL, T₂ = (273.2 + 20.0) K = 293.2 K
Combined gas law: P₁V₁/T₁ = P₂V₂/T₂
Then, V₂ = V₁ × (P₁/P₂) × (T₂/T₁)
Calculated new volume, V₂ = (14.8 mL) × (710/370) × (293.2/284.2) = 29.3 mL
