Answer: ∆p2 = 2* ∆p1
Explanation:
Given that all other factors remain constant. The pressure drop across the pipeline is directly proportional to the length.
i.e ∆p ~ L
Therefore,
∆p2/L2 = ∆p1/L1
Since L2 = 2 * L1
∆p2/2*L1 = ∆p1/L1
Eliminating L1 we have,
∆p2/2 = ∆p1
Multiplying both sides by 2
∆p2 = 2 * ∆p1
Answer:
offense or defense
Explanation:
i could be wrong so dont use my answer if you REALLY need help
Well in my opinion I think that is called gravity but I’m no expert.
Answer:
0.536 A
Explanation:
From the question,
The combined resistance of the parallel connection is given as
1/Rt = 1/4+1/6+1/10
Rt = 120/15
Rt = 8 ohms.
Since the the combination is connected in series with a 10 ohms resistor,
Rt' = 8+10 = 18 ohms.
Current flowing through the series circuit
I = V/Rt'
V = 12 V, Rt' = 18 ohms
I = 12/18
I = 0.67 A.
Therefore voltage across the combined resistor
V' = 8(0.67)
v' = 5.36 V.
Since the resistors a connected in parallel, the same voltage drop across them.
Therefore, current through the 10 ohms
Ix = 5.36/10
Ix = 0.536 A