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amm1812
3 years ago
14

A student obtained a clean flask. She weighed the flask and stopper on an analytical balance and found the total mass to be 34.2

32 g. She then filled the flask with water and found the new mass to be 60.167 g. The temperature of the water was measured to be
Chemistry
1 answer:
DanielleElmas [232]3 years ago
3 0

Answer:

25.99mL is the volume internal volume of the flask

Explanation:

<em>To complete the question:</em>

<em>The temperature of the water was measured to be 21ºC. Use this data to find the internal volume of the stoppered flask</em>

<em />

The flask was filled with water, that means the internal volume of the flask is equal to the volume that the water occupies.

To find the volume of the water you need to find the mass and by the use of density of water at 21ºC (0.997992g/mL), you can find the volume of the flask, thus:

Mass water = Mass filled flask - Mass of clean flask

Mass water = 60.167g - 34.232g

Mass water = 25.935g of water.

To convert this mass to volume:

25.935g × (1mL / 0.997992g) =

<h3>25.99mL is the volume internal volume of the flask</h3>
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erik [133]
<span>Hello!
 
The statement that best proves that the law of conservation is obeyed during this process is that </span><span>The total mass of oxygen and carbon is equal to the total mass of carbon dioxide.

The chemical equation for the combustion reaction of coal in the carbon cycle is the following one:

C(s) + O</span>₂(g) → CO₂(g)
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From this simple chemical equation, we can conclude that if the Law of Conservation of Matter is obeyed in this reaction, the sum of the initial masses of Carbon and Oxygen before the reaction will be equal to the total amount of Carbon Dioxide formed by it, because they sum up to produce Carbon Dioxide.

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4 0
3 years ago
Read 2 more answers
The density of ethanol, C 2H 5OH, is 0.789 g/mL. How many milliliters of ethanol are needed to produce 25.0 g of CO 2 according
gogolik [260]

Answer:

11.1mL

Explanation:

The reaction expression is given as:

          C₂H₅OH   + 3O₂ → 2CO₂ +  3H₂O

Given parameters:

density of ethanol  = 0.789g/mL

mass of CO₂ = 25g

Unknown:

Volume of ethanol = ?

Solution:

First find the number of moles of the CO₂ from the given mass;

 Number of moles  = \frac{mass}{molar mass}

 Molar mass of CO₂ = 12 + 2(16) = 44g/mol

Number of moles  = \frac{25}{44}    = 0.57mol

Then;

 Find the number of moles of ethanol used;

     3 moles of CO₂ is produced from 1 mole of ethanol;

    0.57mole of CO₂ will be produced from \frac{0.57}{3}  = 0.19mole of ethanol

Now;

Find the mass of the ethanol from the given mole;

     Mass of ethanol  = number of moles x molar mass

     Molar mass of ethanol  = 2(12) + 5(1) + 16 + 1 = 46g/mol

      Mass of ethanol  = 0.19 x 46 = 8.74g

Then;

  Density is the mass per unit volume of a substance;

       Density  = \frac{mass}{volume}

        Volume  = \frac{mass}{density}  

          Volume  = \frac{8.74}{0.789}   = 11.1mL

5 0
3 years ago
13. Copper(II) chloride and silver acetate Acid/Base:
Lubov Fominskaja [6]

Answer:

13. CuCl_2 \hspace{0.1cm}+ CH_3COOAg -> AgCl \hspace{0.1cm} + (CH_3COO)_2Cu

This is a double displacement reaction, not an acid-base reaction

14.HF\hspace{0.1cm}+Ba(OH)_2 ->\hspace{0.1cm}H_2O\hspace{0.1cm}+BaF_2

Ba(OH)_2 -> Base

HF -> Acid

15. HCl\hspace{0.1cm}+Mg(OH)_2->\hspace{0.1cm}H_2O\hspace{0.1cm}+MgCl_2

MgCl_2 -> Base

HCl -> Acid

16.CH_3COOH\hspace{0.1cm}+LiOH->\hspace{0.1cm}H_2O\hspace{0.1cm}+CH_3COOLi

LiOH -> Base

CH_3COOH -> Acid

17.H_2SO_4\hspace{0.1cm}+NaOH->\hspace{0.1cm}H_2O\hspace{0.1cm}+NaHSO_4

NaOH -> Base

H_2SO_4-> Acid

18. H_2SO_4\hspace{0.1cm}+NaOH->\hspace{0.1cm}H_2O\hspace{0.1cm}+NaHSO_4

NaOH -> Base

H_2SO_4-> Acid

19.H_2SO_4\hspace{0.1cm}+NaHCO3->\hspace{0.1cm}H_2O\hspace{0.1cm}+CO_2+\hspace{0.1cm}Na_2SO_4

NaHCO_3-> Base

H_2SO_4-> Acid

20.H_3PO_4\hspace{0.1cm}+Zn(OH)_4->\hspace{0.1cm}H_2O\hspace{0.1cm}+Zn_3(PO_4)_4

Zn(OH)_4> Base

H_3PO_4-> Acid

21. HF\hspace{0.1cm}+Na_2SO_3->\hspace{0.1cm}H_2O\hspace{0.1cm}+NaF\hspace{0.1cm}+\hspace{0.1cm}SO_2

NaSO_2> Base

HF-> Acid

22.HCl\hspace{0.1cm}+Na_2SO_3->\hspace{0.1cm}H_2O\hspace{0.1cm}+NaCl\hspace{0.1cm}+\hspace{0.1cm}SO_2

NaSO_2> Base

HCl-> Acid

23.HCl\hspace{0.1cm}+Na_2S->\hspace{0.1cm}H_2S\hspace{0.1cm}+NaCl

Na_2S> Base

HCl-> Acid

24. NH_4Cl\hspace{0.1cm}+NaOH->\hspace{0.1cm}H_2O\hspace{0.1cm}+NaCl+{0.1cm}NH_3

NaOH> Base

NH_4Cl-> Acid

Explanation:

All acid-base reaction have the same products, H_2O and a salt. Whit this in mind the acids would the compounds that produces the hydronium ion (H^+) and the bases would be the compounds that produces the hydroxide ion (OH^-)

8 0
3 years ago
A chemist determined by measurements that 0.015 moles of iron participated in a chemical reaction. Calculate the mass of iron th
exis [7]

Answer: 0.84 g

Explanation:

\text{ Mass of iron}=\text{ Moles of iron}\times \text{ Molar mass of iron}

Given: moles of iron = 0.015

Molar mass of iron = 56 g/mol

\text{ Mass of iron}=0.015\times 56g/mol=0.84g

Thus 0.84 g of iron participated in the chemical reaction.

7 0
3 years ago
What is the observation of heating copper carbonate???.?
damaskus [11]

Answer:

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Explanation:

hope this helps you :)

7 0
3 years ago
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