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3 years ago

Please could you help me with this question

Chemistry

2 answers:

Serga [27]3 years ago

8 0

The one on the left is pure because it is made out of one single material. The one on the right is a mixture because it is made out of multiple materials

matrenka [14]3 years ago

4 0

Answer:

first one pure

second one mixture..

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Drug testing if a person do not use drugs how cam he test positive on hair drug test

Hitman42 [59]

For example, certain medications may influence the results of the test.

Drug test can show the presence of illicit or prescription drugs on hair samples, although the person has not used these drugs.

Some of false positive drug use is because of this medications: antihistamines, decongestants, antibiotics, antidepressants, analgesics and antipsychotics.

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3 years ago

A(n) ______ Is a group of organs that work together to perform a com

soldier1979 [14.2K]

Answer:

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Explanation:

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2 years ago

At 25 °C, how many dissociated OH– ions are there in 1243 mL of an aqueous solution whose pH is 2.07?

coldgirl [10]

Answer: The number of $OH^-$ ions dissociated are $8.57\times 10^{11}$

Explanation:

We are given:

pH = 2.07

Calculating the value of pOH by using equation, we get:

$2.07+pOH=14\\\\pOH=14-2.07=11.93$

To calculate hydroxide ion concentration, we use the equation to calculate pOH of the solution, which is:

$pOH=-\log[OH^-]$

We are given:

pOH = 11.93

Putting values in above equation, we get:

$11.93=-\log[OH^-]$

$[OH^-]=10^{-11.93}=1.17\times 10^{-12}M$

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of solution = $1.17\times 10^{-12}M$

Volume of solution = 1243 mL = 1.243 L (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

$1.17\times 10^{-12}M=\frac{\text{Moles of }OH^-}{1.243L}\\\\\text{Moles of }OH^-=(1.17\times 10^{-12}mol/L\times 1.243L)=1.424\times 10^{-12}mol$

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of particles

So, $1.424\times 10^{-12}mol$ number of $OH^-$ will contain = $(1.424\times 10^{-12}\times 6.022\times 10^{23})=8.57\times 10^{11}$ number of ions

Hence, the number of $OH^-$ ions dissociated are $8.57\times 10^{11}$

3 0

3 years ago

Examples of nitrogens unreactivity

REY [17]

WATCH OUT BUDDY:reactivity....Spelling mistake.

ANSWER:
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3 years ago

When solutions of silver nitrate and sodium chloride are mixed, a precipitation reaction occurs. What mass of precipitate can be

Bas_tet [7]

Explanation:

The given precipitation reaction will be as follows.

$AgNO_{3}(aq) + NaCl(aq) \rightarrow AgCl(s) + NaNO_{3}(aq)$