Below is the solution:
Let us say that the disk goes through a vertical elevation change of one meter.
<span>The change in potential energy will equal the change in kinetic energy </span>
<span>PE = KEt + KEr </span>
<span>mgh = ½mv² + ½Iω² </span>
<span>for a uniform disk, the moment of inertia is </span>
<span>I = ½mr² </span>
<span>and </span>
<span>ω = v/r </span>
<span>mgh = ½mv² + ½(½mr²)(v/r)² </span>
<span>mgh = ½mv² + ¼mv² </span>
<span>gh = ¾v² </span>
<span>v² = 4gh/3 </span>
<span>v² = u² + 2as </span>
<span>if we assume initial velocity is zero </span>
<span>v² = 2as </span>
<span>a = v² / 2s </span>
<span>s(sinθ) = h </span>
<span>s = h/sinθ </span>
<span>a = 4gh/3 / 2(h/sinθ) </span>
<span>a = ⅔gsinθ </span>
<span>a = ⅔(9.8)sin25 </span>
<span>a = 2.8 m/s² </span>
I’d say D sorry if I was wrong
Answer:
C. Distance does not affect the force of gravity.
Answer:
21 m/s
Explanation:
There are three forces on the pendulum:
Weight force mg pulling down,
Vertical tension component Tᵧ pulling up,
and horizontal tension component Tₓ pulling towards the center of the curve.
Sum of forces in the y direction:
∑F = ma
Tᵧ − mg = 0
T cos 37° = mg
T = mg / cos 37°
Sum of forces in the centripetal direction:
∑F = ma
Tₓ = mv²/r
T sin 37° = mv²/r
(mg / cos 37°) sin 37° = mv²/r
g tan 37° = v²/r
v = √(gr tan 37°)
v = √(9.8 m/s² × 60 m × tan 37°)
v = 21 m/s
We're going to remedy it with the parallelogram law.
= one hundred eighty - 30 - 70 = eighty degrees
R = sqrt(2^2 + 3^2 - 2(2)(three) cos(80)
R = three.30 kN, we can conclude now that the value of the ensuing of R is 3.30 kN
sin
/3 = sin(eighty)/three.304 = 63.4 stages
3.3 kN
180 + 33.4 = 213.4 degrees
63.4 - 30 = 33.4