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Pepsi [2]
3 years ago
13

The circulating flow of air resulting from temperature differences is called a

Chemistry
1 answer:
IceJOKER [234]3 years ago
8 0

Answer:

Explanation:convection or advection

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Which type of bond will most likely be found in HBr?
NARA [144]
<span>HBr is covalent bond.!

</span>Hydrogen and Bromine will share their electrons, to obtain the electron configuration of a noble gas<span>.
</span>
hope this helps!

6 0
3 years ago
Read 2 more answers
When the volume of a gas is
Montano1993 [528]

Answer:

\boxed {\boxed {\sf 232.9 \textdegree C}}

Explanation:

This question asks us to find the temperature change given a volume change. We will use Charles's Law, which states the volume of a gas is directly proportional to the temperature. The formula is:

\frac {V_1}{T_1}= \frac{V_2}{T_2}

The volume of the gas starts at 250 milliliters and the temperature is 137 °C.

\frac{250 \ mL}{137 \textdegree C}= \frac{V_2}{T_2}

The volume of the gas is increased to 425 milliliters, but the temperature is unknown.

\frac{250 \ mL}{137 \textdegree C}= \frac{425 \ mL}{T_2}

We are solving for the new temperature, so we must isolate the variable T₂. First, cross multiply. Multiply the first numerator and second denominator, then multiply the first denominator and second numerator.

250 \ mL * T_2 = 137 \textdegree C * 425 \ mL

Now the variable is being multiplied by 250 milliliters. The inverse of multiplication is division. Divide both sides of the equation by 250 mL.

\frac{250 \ mL * T_2}{250 \ mL}=\frac{ 137 \textdegree C * 425 \ mL}{250 \ mL}

T_2=\frac{ 137 \textdegree C * 425 \ mL}{250 \ mL}

The units of milliliters (mL) cancel.

T_2=\frac{ 137 \textdegree C * 425 }{250 }

T_2= \frac{58225}{250} \textdegree C

T_2=232.9 \textdegree C

The temperature changes to <u>232.9 degrees Celsius.</u>

3 0
3 years ago
A blank observation is when you describe something
lana [24]
The correct answer would be... Scientific
8 0
3 years ago
At what temperature is water at its greatest density​
ahrayia [7]

Answer:

3.98^oC

Explanation:

We usually approximate the density of water to about 1000 kg/m^3 at room temperature. In terms of the precise density of water, this is not the case, however, as density is temperature-dependent.

The density of water decreases with an increase in temperature after the peak point of its density. The same trend might be spotted if the temperature of water is decreased from the peak point.

This peak point at which the density of water has the greatest value is usually approximated to about 4^oC. For your information, I'm attaching the graph illustrating the function of the density of water against temperature where you could clearly indicate the maximum point.

To a higher precision, the density of water has a maximum value at 3.98^oC, and the density at this point is exactly 1000 kg/m^3.

6 0
3 years ago
Read 2 more answers
A sample of carbon dioxide is contained in a 250.0 mL flask at 0.930 atm and 15.4 °C. How many molecules of gas are in
Yanka [14]

Answer:

We are given:

Volume (V) = 0.25 L

Pressure (P) = 0.93 atm

Temperature (T) = 15.4°C  OR   288.4 K

<u>Solving for the number of moles of CO₂:</u>

From the ideal gas equation:

PV = nRT

replacing the variables

0.93 * 0.25 = n (0.082)(288.4)

n = 0.00983 moles

<u>Number of molecules:</u>

Number of moles=  0.00983

number of molecules in 1 mole = 6.022 * 10²³

Number of molecules in 0.00983 moles = 0.00983 * 6.022 * 10²³

Number of molecules = 5.91 * 10²¹

8 0
3 years ago
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