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3 years ago

How many words can the word DEOXYRIBONUCLEIC ACID make

Chemistry

2 answers:

denis23 [38]3 years ago

7 0

You can make as many as you want to make

Lesechka [4]3 years ago

3 0

Answer: four hundred and 18

Explanation:

Simple math showed that only 16 words are possible from a two-letter combination, but a three-letter code produces 64 words. Operating on the principle that the simplest solution is often correct, researchers assumed a three-letter code called a codon.

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Aqueous sulfuric acid will react with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . Suppose 0.98 g

cestrela7 [59]

Answer:

0.43 grams is the maximum mass of sodium sulfate that could be produced by the chemical reaction.

Explanation:

Mass of sulfuric acid = 0.98 g

Moles of sulfuric acid = $\frac{0.98 g}{98 g/mol}=0.010 mol$

Mass of sodium hydroxide = 0.240 g

Moles of sodium hydroxide = $\frac{0.240 g}{40 g/mol}=0.0060 mol$

$H_2SO_4(aq)+2NaOH(s)\rightarrow Na_2SO_4(aq)+2H_2O(l)$

According to reaction, 2 moles of sodium hydroxide reacts with 1 mole of sulfuric acid , then 0.0060 moles of sodium hydroxide will react with :

$\frac{1}{2}\times 0.0060 mol=0.0030 mol$ of sulfuric acid

As we can see that we have 0.010 moles of sulfuric acid but only 0.0030 moles of sulfuric acid will react which indicates that it is in excessive amount where as sodium hydroxide is in limiting amount.

So, amount of sodium sulfate to be formed will depend upon moles of sodium hydroxide.

According to reaction, 2 moles of sodium hydroxide gives with 1 mole of sodium sulfate , then 0.0060 moles of sodium hydroxide will give :

$\frac{1}{2}\times 0.0060 mol=0.0030 mol$ of sodium sulfate

Mass of 0.0030 moles of sodium sulfate :

0.0030 mol × 142 g/mol = 0.426 g ≈ 0.43 g

0.43 grams is the maximum mass of sodium sulfate that could be produced by the chemical reaction.

4 0

3 years ago

PLEASE HELP!!!!!!!!! 12 POINTS!!!!!!!

Nimfa-mama [501]

Ocean-dwelling I would say.

4 0

3 years ago

Read 2 more answers

Please help due today

Olegator [25]

1,1,2 & single replacement reaction

4 0

3 years ago

How do you get from mass to moles in this problem?

Zinaida [17]

Answer:

what problem?

8 0

3 years ago

At a certain temperature the vapor pressure of pure chloroform (CHCl3) is measured to be 91. torr. Suppose a solution is prepare

OleMash [197]

Answer:

$P_{CCl_4}=52.43torr$

Explanation:

Hello there!

In this case, sine the solution of this problem require the application of the Raoult's law, assuming heptane is a nonvolatile solute, so we can write:

$P_{CCl_4}=x_{CCl_4}P_{CCl_4}^{vap}$

Thus, we first calculate the mole fraction of chloroform, by using the given masses and molar masses as shown below:

$x_{CCl_4}=\frac{140/153.81}{140/153.81+67.1/100.21}=0.576$

Therefore, the partial pressure of chloroform turns out to be:

$P_{CCl_4}=0.576*91torr\\\\P_{CCl_4}=52.43torr$

Regards!

3 0

3 years ago