All categories

3 years ago

How are protons, neutrons be, and electrons similar?

Chemistry

2 answers:

Blababa [14]3 years ago

8 0

Answer:

This is how

Explanation:

Protons and neutrons have approximately the same mass, but they are both much more massive than electrons (approximately 2,000 times as massive as an electron). The positive charge on a proton is equal in magnitude to the negative charge on an electron.

lord [1]3 years ago

4 0

Answer: They are all subatomic particles that make up an atom.

You might be interested in

What is the nucleus of an atom?

Leno4ka [110]

Answer:

The atomic nucleus is the small, dense region consisting of protons and neutrons at the center of an atom, discovered in 1911 by Ernest Rutherford based on the 1909 Geiger–Marsden gold foil experiment.

5 0

2 years ago

0.10 M potassium chromate is slowly added to a solution containing 0.20 M AgNO3 and 0.20 M Ba(NO3)2. What is the Ag+ concentrati

erastova [34]

Answer:

$[Ag^{+}]=4.2\times 10^{-2}M$

Explanation:

Given:

[AgNO3] = 0.20 M

Ba(NO3)2 = 0.20 M

[K2CrO4] = 0.10 M

Ksp of Ag2CrO4 = 1.1 x 10^-12

Ksp of BaCrO4 = 1.1 x 10^-10

$BaCrO_4 (s)\leftrightharpoons Ba^{2+}(aq)\;+\;CrO_{4}^{2-}(aq)$

$Ksp=[Ba^{2+}][CrO_{4}^{2-}]$

$1.2\times 10^{-10}=(0.20)[CrO_{4}^{2-}]$

$[CrO_{4}^{2-}]=\frac{1.2\times 10^{-10}}{(0.20)}= 6.0\times 10^{-10}$

Now,

$Ag_{2}CrO_4(s) \leftrightharpoons 2Ag^{+}(aq)\;+\;CrO_{4}^{2-}(aq)$

$Ksp=[Ag^{+}]^{2}[CrO_{4}^{2-}]$

$1.1\times 10^{-12}=[Ag^{+}]^{2}](6.0\times 10^{-10})$

$[Ag^{+}]^{2}]=\frac{1.1\times 10^{-12}}{(6.0\times 10^{-10})}= 1.8\times 10^{-3}$

$[Ag^{+}]=\sqrt{1.8\times 10^{-3}}=4.2\times 10^{-2}M$

So, BaCrO4 will start precipitating when [Ag+] is 4.2 x 1.2^-2 M

7 0

3 years ago

100 POINTS!!!

Paul [167]

what do u need help with u pls respond quickly

6 0

2 years ago

Read 2 more answers

stiks02 [169]

Answer:

An organ is a part of the body that carries out its main function. Most organs are made out of tissues.

Explanation:

6 0

3 years ago

Read 2 more answers

In an oxidation–reduction reaction, what happens to the electrons in the oxidation process? A. Electrons are bonded. B. Electron

DanielleElmas [232]

Answer: C. Electrons are lost.

Explanation:

The oxidation reduction reaction is between oxidizing agent and reducing agent.

The oxidizing agent gains electrons and reduction process occurs to it, while the reducing agent losses electrons and oxidation process occurs to it.

oxidizing agent + ne → product "reduction process, gain electrons"

reducing agent → product + ne "oxidation process, loss electrons"

Thus, The right answer is: in the oxidation process, electrons are lost.

7 0

3 years ago

Read 2 more answers