3. How many molecules of C9H304 are there in .1g of it?
1 answer:
Answer:
3 × 10²⁰ molecules C₉H₃O₄
Explanation:
Step 1: Define
Avagadro's Number: 6.02 × 10²³ atoms, molecules, formula units, etc.
Molar Mass C - 12.01 g/mol
Molar Mass H - 1.01 g/mol
Molar Mass O - 16.00 g/mol
Molar Mass C₉H₃O₄ - 175.12 g/mol
Step 2: Use Dimensional Analysis
= 3.43764 × 10²⁰ molecules C₉H₃O₄
Step 3: Simplify
We are give 1 sig fig.
3.43764 × 10²⁰ molecules C₉H₃O₄ ≈ 3 × 10²⁰ molecules C₉H₃O₄
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Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.
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