All categories

3 years ago

What is the speed of a truck that travels 15 KM in 12 minutes

2 answers:

8 0

First you need to find out how many kilometers it travels for 60 minutes:
15km*60minutes = 900 Kilometers
Then you divide the distance traveled in one hour by 12 :
900kilometers/12minutes = 75km/h or 47mph

Liono4ka [1.6K]3 years ago

5 0

Speed equals distance divided by time. 15km divided by 12 minutes equals 1.25 km/minute.

You might be interested in

A person, with his ear to the ground, sees a huge stone strike the concrete pavement. A moment later two sounds are heard from t

s344n2d4d5 [400]

Answer:

309 m

Explanation:

time apart = 0.8 s

speed of sound in air = 343 m/s

speed of sound in concrete = 3000 m/s

lets assume it time it takes to travel trough concrete = T

the time it takes to travel through air = T + 0.8 since they are 0.8 s apart

the distance traveled by both waves is the same, so we can equate the distance for both waves

distance = speed x time

for concrete, distance = 3000 x T
for air, distance = 343 x (T + 0.8)

now equating the two distance together we have

3000 x T = 343 x (T + 0.8)

3000T = 343T + 274.4

3000T - 343T = 274.4

T = 0.103 s

recall that distance = 3000 x T = 3000 x 0.103 = 309 m

5 0

3 years ago

Determine the stopping distances for a car with an initial speed of 88 km/h and human reaction time of 2.0 s for the following a

seropon [69]

Explanation:

Given that,

Initial speed of the car, u = 88 km/h = 24.44 m/s

Reaction time, t = 2 s

Distance covered during this time, $d=24.44\times 2=48.88\ m$

(a) Acceleration, $a=-4\ m/s^2$

We need to find the stopping distance, v = 0. It can be calculated using the third equation of motion as :

$s=\dfrac{v^2-u^2}{2a}$

$s=\dfrac{-(24.44)^2}{2\times -4}$

s = 74.66 meters

s = 74.66 + 48.88 = 123.54 meters

(b) Acceleration, $a=-8\ m/s^2$

$s=\dfrac{v^2-u^2}{2a}$

$s=\dfrac{-(24.44)^2}{2\times -8}$

s = 37.33 meters

s = 37.33 + 48.88 = 86.21 meters

Hence, this is the required solution.

4 0

4 years ago

What is the cooling power P? Recall that the rate at which energy is removed, also called the cooling power, was described earli

gayaneshka [121]

Answer:

36.667

Explanation:

(2.2*10^4)/(10*60)

3 0

3 years ago

The liquid in the cup is brown" is an example of an ..............

erastova [34]

Eaither D or A bit I am leaning more towards D

3 0

3 years ago

Read 2 more answers

Capacitors C1 = 5.85 µF and C2 = 2.80 µF are charged as a parallel combination across a 250 V battery. The capacitors are discon

posledela

Answer:

Q1_new = 515.68 µC

Q2_new = 246.82 µC

Explanation:

Since the capacitors are charged in parallel and not in series, then both are at 250 V when they are disconnected from the battery.

Then it is only necessary to calculate the charge on each capacitor:

Q1 = 5.85 µF * 250 V = 1462.5 µC

Q2 = 2.8 µF * 250 V = 700 µC

Now, we will look at 1462.5 µC as excess negative charges on one plate, and 1462.5 µC as excess positive charges on the other plate. Now, we will use this same logic for the smaller capacitor.

When there is a connection of positive plate of C1 to the negative plate of C2, and also a connection of the negative plate of C1 to the positive plate of C2, some of these excess opposite charges will combine and cancel each other. The result is that of a net charge:

1462.5 µC - 700 µC = 762.5 µC

Thus,762.5 µC of net charge will remain in the 'new' positive and negative plates of the resulting capacitor system.

This 762.5 µC will be divided proportionately between the two capacitors.

Q1_new = 762.5 µC * (5.85/(5.85 + 2.8)) = 515.68 µC

Q2_new = 762.5 µC * (2.8/(5.85 + 2.8) = 246.82 µC

4 0

4 years ago