With the use of electric force formula, the direction and magnitude of the net force exerted on the point charge q3 are 9.9 x N and 66 degrees
ELECTRIC FORCE (F)
F =
Where K = 9 x N/
The distance between and can be calculated by using Pythagoras theorem.
d =
d = 46.7 cm = 0.467 m
For force , substitute all the parameters into the formula above
= (9 x x 3 x 1)/
= 2.7 x /0.218
= 1.24 x N
For force , substitute all the parameters into the formula above
= (9 x x 3 x 4)/
= 1.08 x /0.1089
= 9.92 x N
For force , substitute all the parameters into the formula above
= (9 x x 3 x 2)/
= 5.4 x /0.1089
= 4.96 x N
Summation of forces on Y component will be
= - Sin 45
= 9.92 x - 1.24 x Sin 45
= 9.04 x N
Summation of forces on X component will be
= - Cos 45
= 4.96 x - 1.24 x Sin 45
= 4.08 x N
Net Force =
Net force =
Net force = 9.9 x N
The direction will be
Tan ∅ = /
Tan ∅ = 9.04 x / 4.08 x
Tan ∅ = 2.216
∅ = (2.216)
∅ = 65.7 degrees
Therefore, the direction and magnitude of the net force exerted on the point charge q3 are 9.9 x N and 66 degrees approximately.
Learn more about electric Force here: brainly.com/question/4053816
The image of the object is 8cm to the left of the lens (D)
<h3>
</h3>
What is the image of an object?
The image of an object is said to be the location where light rays from that object intersect with a mirror by reflection.
It is calculated thus:
1÷v = 1÷f - 1÷u
<h3>How to calculate the image of an object</h3>
From the formula
1÷v = 1÷f - 1÷u
<h3>
Where </h3>
V = image distance fromthe object
U = object
f = focal length
Substitute the values
1÷v = 1÷8 - 1÷ 4
1÷v = - 1÷8
Make v the subject of formula
v = -8cm
Therefore, the image of the object is 8cm to the left of the lens (D)
Learn more on focal length here:
brainly.com/question/25779311
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