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irakobra [83]
3 years ago
5

WILL GIVE BRAINLIEST!:)

Chemistry
1 answer:
nalin [4]3 years ago
4 0
I am sorry but do not listen to the link above it is a virus and it will be installed if you do stay safe and spread the word
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The pressure of a gas depends on the ____ and ____ of the gas.
dexar [7]

The pressure of a gas depends on the temperature and volume of the gas.

<h3>Ideal gas equation</h3>

PV = nRT

Where

  • P is the pressure
  • V is the volume
  • n is the number of mole
  • R is the gas constant
  • T is the temperature

From the equation given above, we obtained the following:

PV = nRT

Divide both sides by V

P = nRT / V

R is constant and n = 1

P = T / V

Thus, we can see that the pressure (P) is dependent on the temperature (T) and the volume (V)

Learn more about ideal gas equation:

brainly.com/question/4147359

#SPJ11

4 0
2 years ago
Read 2 more answers
How many moles of water are produced from 0.500 moles of oxygen gas?
solmaris [256]
As far as I know NONE.....
Explanation:
Sodium peroxide can be thermolyzed to give dioxygen gas...
N
a
2
O
2
(
s
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+
Δ
→
N
a
2
O
(
s
)
+
1
2
O
2
(
g
)
↑
⏐
⏐
⏐

But with water, we simply get an acid base reaction....
N
a
2
O
2
(
s
)
+
2
H
2
O
(
l
)
→
2
N
a
O
H
(
a
q
)
+
H
2
O
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(
a
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...
6 0
3 years ago
The formula for density is ____ divided by volume.<br><br> mass<br><br> ounces<br><br> weight
neonofarm [45]
The answer is mass which is also m/v=d
8 0
4 years ago
Read 2 more answers
Which of these is an appropriate instrument to measure mass?
iris [78.8K]

Answer: Balance

Explanation:

8 0
3 years ago
Write the Henderson-Hasselbalch equation for a propanoic acid solution ( CH3CH2CO2H , pKa=4.874 ) using the symbols HA and A− ,
zysi [14]

Answer:

a) [A⁻]/[HA] = 0.227

b) [A⁻]/[HA] = 0.991

c) [A⁻]/[HA] = 2.667

Explanation:

In the Henderson-Hasselbalch equation, HA stands from an acid an A⁻ stands from its conjugate base, as follows:

  • CH₃CH₂CO₂H = HA
  • CH₃CH₂CO₂⁻ = A⁻

pH = pka + Log [A⁻]/[HA]

pH = 4.874 + Log[CH₃CH₂CO₂⁻]/[CH₃CH₂CO₂H]

  • (a)

4.23 = 4.874 + Log [A⁻]/[HA]

-0.644 = Log [A⁻]/[HA]

10^{-0.644} = [A⁻]/[HA]

0.227 = [A⁻]/[HA]

  • (b)

4.87 = 4.874 + Log [A⁻]/[HA]

-0.004 = Log [A⁻]/[HA]

10^{-0.004} = [A⁻]/[HA]

0.991 = [A⁻]/[HA]

  • (c)

5.30 = 4.874 + Log [A⁻]/[HA]

0.426 = Log [A⁻]/[HA]

10^{0.426} = [A⁻]/[HA]

2.667 = [A⁻]/[HA]

6 0
4 years ago
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