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3 years ago

8

Need help fast please

1 answer:

fenix001 [56]3 years ago

5 0

Explanation:

When the reaction takes place,2 grams of carbon dioxide will be made but vaporized into air.

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When a solution forms, what interactions between particles are involved? Which are exothermic? Which are endothermic?

Blizzard [7]

Answer:

Explanation:

There are three types of interactions involved between the particles when solution are formed.

1 : Solute - solute interaction:

2 : Solute - solvent interaction:

3 : Solvent - solvent interaction:

1 : Solute - solute interaction:

It is the inter-molecular attraction between the solute particles.

2 : Solute - solvent interaction:

It involve the inter-molecular attraction between solvent and solute particles.

3 : Solvent - solvent interaction:

It involve the intermolecular attraction between solvent particles.

Solutions are formed if the intermolecular attraction between solute particles are similar to the attraction between solvent particles.

Exothermic process:

The process will exothermic when solute solvent bonds are formed with the release of energy and energy required to brake the solute-solute particles and solvent solvent particles are less.

Endothermic process:

The process will be endothermic when energy required to break the solute-solute particles and solvent solvent particles are higher than energy released when solute solvent bonds are formed .

6 0

3 years ago

56. The electron configuration for phosphorous is [Ar]3s23p4.<br> a. TRUE<br> b. FALSE

melomori [17]

Answer:

False

Explanation:

7 0

2 years ago

Read 2 more answers

Suppose of hcl and of o2 are added to an empty flask. How much will be in the flask at equilibrium?A. None. B. Some, but less th

serg [7]

This is an incomplete question, here is a complete question.

Hydrogen chloride and oxygen react to form water and chlorine, like this:

$4HCI(g)+O_2(g)\rightarrow 2H_2(g)+2CI_2(g)$

Use this chemical equation to answer the questions in the table below.

Suppose 155. mmol of HCl and 38.8 mmol of O₂ are added to an empty flask. How much HCl will be in the flask at equilibrium?

(1) None.

(2) Some, but less than 155. mmol,

(3) 155. mmol,

(4) More than 155. mmol,

Answer : The correct option is, (1) None

Explanation :

The given balanced chemical reaction is:

$4HCI(g)+O_2(g)\rightarrow 2H_2(g)+2CI_2(g)$

From the balanced chemical reaction, we conclude that

As, 4 mmole of HCl react with 1 mmoles of $O_2$

So, 155. mmole of HCl react with $\frac{155.}{4}\times 1=38.75$ mmoles of $O_2$

That means, $O_2$ is excess reagent and $HCl$ is a limiting reagent. All the moles of HCl will consume.

Hence, the correct option is, None.

7 0

3 years ago

How can liquid reach higher temperatures in a pressure cooker than in an unsealed pot?

Alex_Xolod [135]

Answer:

the heat is circulating in the same spot rather than airing out into the open

Explanation:

4 0

4 years ago

Read 2 more answers

When 100.0 g block of a metal at 600 oC is plunged into 100.0 g of water (specific heat capacity 4.2 J/g.oC) at 30 oC, the final

kozerog [31]

Answer: $0.40J/g^0C$

Explanation:

$heat_{released}=heat_{absorbed}$

As we know that,

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

$-[m_1\times c_1\times (T_{final}-T_1)]=[m_2\times c_2\times (T_{final}-T_2)]$ .................(1)

where,

q = heat absorbed or released

$m_1$ = mass of metal = 100.0 g

$m_2$ = mass of water = 100.0 g

$T_{final}$ = final temperature = $80^0C$

$T_1$ = temperature of metal = $600^oC$

$T_2$ = temperature of water = $30^oC$

$c_1$ = specific heat of metal = ?

$c_2$ = specific heat of water= $4.2J/g^0C$

Now put all the given values in equation (1), we get

$-[100.0\times c_1\times (80-600)]=[100.0\times 4.2\times (80-30)]$

$c_1=0.404J/g^0C$

Therefore, the specific heat capacity of metal is $c_1=0.40J/g^0C$

4 0

3 years ago