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gavmur [86]
3 years ago
5

why is it important to consider the position, direction and speed of an object when describing its motion?

Physics
1 answer:
Gennadij [26K]3 years ago
5 0

Answer:

An object's motion depends on how it changes position. Motion can be described using speed, velocity, or acceleration. Speed is how fast an object moves. Velocity describes an object's speed and the direction it moves.

Explanation:

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Time = distance / speed
T = 125/ 5
T = 25 meters per second
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A force of attraction would exist between
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D. two positively charged objects

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"State the process that divides one nucleus into two genetically identical nuclei"
kompoz [17]

Answer:

<em>Mitosis</em>

Explanation:

Mitosis: Mitosis is a cell or nuclear division following the duplicate of the chromosomes, whereby each daughter cell or nucleus has exactly the same chromosomes content as the parent. In other words, mitosis is a cell division in which daughter cells have the same number of chromosomes as the parent cell.

Mitosis takes place during organism's growth, development, and asexual reproduction. in plants mitosis takes place in the terminal bud of the shoot at the tip of the roots and shoots. In animal mitosis occur at growth centres which are everywhere.

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Example of mitosis is the multiplication of the skin covering a child's body during growth

4 0
3 years ago
A child's top is held in place upright on a frictionless surface. The axle has a radius of ????=3.21 mm . Two strings are wrappe
tekilochka [14]

Answer:

Angular momentum, L=6.47\times 10^{-3}\ m

Explanation:

It is given that,

Radius of the axle, r=3.21\ mm=3.21\times 10^{-3}\ m

Tension acting on the top, T = 3.15 N

Time taken by the string to unwind, t = 0.32 s

We know that the rate of change of angular momentum is equal to the torque acting on the torque. The relation is given by :

\tau=\dfrac{dL}{dt}

Torque acting on the top is given by :

\tau=F\times r

Here, F is the tension acting on it. Torque acting on the top is given by :

\tau=2F\times r

2T\times r=\dfrac{L}{t}

L=2T\times r \times t

L=2\times 3.15\times 3.21\times 10^{-3}\times 0.32

L=6.47\times 10^{-3}\ m

So, the angular momentum acquired by the top is 6.47\times 10^{-3}\ m. Hence, this is the required solution.

7 0
4 years ago
A 2000-kg railway freight car coasts at 4.4 m/s underneath a grain terminal, which dumps grain directly down into the freight ca
ruslelena [56]

Answer:

933. 3kg

Explanation:

We are given that

Mass,m=2000 kg

Initial speed,u=4.4 m/s

We have to find the maximum mass of grain if the speed of loaded freight car must not go below 3.0 m/s.

Final speed,v=3 m/s

By conservation of momentum

Initial momentum=Final momentum

mu=m'v

Substitute the values

2000\times 4.4=m'(3)

m'=\frac{2000\times 4.4}{3}

m'=2.93\times 10^3 kg

Mass of freight loaded car=2933.3 kg

Mass of grains=2933.3-2000=933.3 kg

Hence, the maximum  mass of grains that it can accept=933.3 kg

7 0
3 years ago
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