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MrRissso [65]
4 years ago
15

What angular speed (in revolutions/second) is needed for a centrifuge to produce an acceleration of 1 000 g at a radius arm of 1

5.0 cm?
a. 40.7 rev's

b. 75.4 rev/s

c. 81.4 rev/s

d. 151 rev/s
Physics
1 answer:
TiliK225 [7]4 years ago
3 0

Answer:

a. 40.7 rev's

Explanation:

"Centrifugal force" is the apparent force that a non-inertial observer seems to perceive as a result of the non-inertiality of his reference system. Therefore, in this case we must work with an equivalent force, that is, the centripetal force, which is given by:

F_c=ma_c

The centripetal acceleration is defined as:

a_c=\frac{v^2}{r}

The linear speed is given by:

v=\omega r

So, we have:

a_c=\frac{(\omega r)^2}{r}\\\\a_c=\omega^2 r\\\omega=\sqrt{\frac{a_c}{r}}\\\omega=\sqrt{\frac{1000*9.8\frac{m}{s^2}}{15*10^{-2}m}}\\\omega=255.60\frac{rad}{s}\\\omega=\frac{255.60\frac{rad}{s}}{2\pi}\\\omega=40.7\frac{rev}{s}

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