3 years ago

What number is between 2000 and 2500

Physics

1 answer:

Kitty [74]3 years ago

6 0

If its just a number 2,300 is an answer

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An automobile with tires that have a radius of 0.260 m travels 76000 km before wearing them out. How many revolutions do the tir

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Answer:

Explanation:

circumference of the tyre = 2πr = 2 x 3.14 x 0.26 = 1.6328m

76000km = 76000000m

no of revolutions required

= 76000000/1.6328 = 46546 revolutions.

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3 years ago

A particle moves along the x axis so that its velocity at time t is given by v(t)=

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Answer:

a = 0.7267 , acceleration is positive therefore the speed is increasing

Explanation:

The definition of acceleration is

a = dv / dt

they give us the function of speed

v = - (t-1) sin (t² / 2)

a = - sin (t²/2) - (t-1) cos (t²/2) 2t / 2

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a = -sin 8 - 12 cos 8

remember that the angles are in radians

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3 years ago

A 65.0 kg football player is running at 10.0 m/s downfield when he catches a 0.420 kg football thrown in the same direction but

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Explanation:

Below is an attachment containing the solution.

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3 years ago

Which statement describes a benefit of a model that uses three balls to model the Sun-Earth-Moon system? A. Every aspect of the

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D. It represents a very large, complex system.

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2 years ago

A 0.20-kg mass is oscillating on a spring over a horizontal frictionless surface. When it is at a displacement of 2.6 cm for equ

valentinak56 [21]

Explanation:

The given data is as follows.

mass = 0.20 kg

displacement = 2.6 cm

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Spring potential energy = 2.2 J

Now, we will calculate the total energy present present as follows.

Total energy = Kinetic energy + spring potential energy

= 1.4 J + 2.2 J

= 3.6 Joules

As maximum kinetic energy of the object will be equal to the total energy.

So, K.E = Total energy

= 3.6 J

Also, we know that

K.E = $\frac{1}{2}mv^{2}_{m}$

or, v = $\sqrt{\frac{2K.E}{m}}$

= $\sqrt{2 \times 3.6 J}{0.2 kg}$

= $\sqrt{36}$

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3 years ago