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True [87]
3 years ago
9

PLEASE HELP! Which clade is composed of eukaryotes which are multicellular and heterotrophs? A) Eubacteria B) Fungi C) Plant D)

Animals
Chemistry
2 answers:
USPshnik [31]3 years ago
5 0
I think your answer would be D
Alex17521 [72]3 years ago
5 0

Answer: D) Animals

Explanation:

Eukaryotic organisms are those organisms which exhibit complex cellular composition. They exhibit membrane bound organelles and nucleus is also enclosed inside a membrane which encloses the genetic material of the organisms. Examples include plants, animals and fungi.

Multicellular organisms are those which exhibit multiple layers of the cells to perform a specialized function.

Hetrotrophic organisms are those which are dependent upon other organisms for their food and nourishment.

Among the given options, Animals is the correct option. This is due to the fact that all animals are eukaryotic organisms as they have a membrane bound nucleus and other cellular organelles. All animals are multicellular because of the fact that multicellular system is necessary for performing specialized functions required for survival. They are incapable of synthesizing their own food either by chemosythesis or photosynthesis. They are dependent upon other organisms like plants and other animals for their food.

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Conserving water can save money while protecting the environment. True or False
blagie [28]

Answer: The given statement is true.

Explanation:

Water is a natural resource present in the nature and it is very precious as life without it is impossible.

So, when we unnecessarily use water then it means we are wasting a natural resource that cannot be reproduced again by human beings.

Therefore, more we are able to conserve water more we can protect other human life's and environment also.

If there is shortage of water then its prices will go high and hence we need to pay more for it.

Thus, we can conclude that the statement conserving water can save money while protecting the environment, is true.

3 0
3 years ago
Read 2 more answers
Write the names and symbols for four elements in each of the following categories: (a) nonmetal, (b) metal, (c)metalloid.
Over [174]

Explanation:

Non-metals are the species that are electron deficient and they are able to accept one or more electrons from a donor atom in order to complete their octet.

For  example, carbon (C), nitrogen (N), chlorine, (Cl), phosphorus (P) etc are all non-metals.

Metals are the species that contain more number of electrons in their valence shell and in order to attain stability they easily lose an electron.

For example, sodium (Na), lithium (Li), Beryllium (Be), Magnesium (Mg) etc are all metals.

Metalloids are the species that show properties of both metals and non-metals.

For example, Boron (B), Antimony (Sb), Silicon (Si) and Germanium (Ge) etc are metalloids.

5 0
3 years ago
How does the sun heat<br> the side of the Earth<br> facing away from it?
Evgen [1.6K]

Answer:

The sun radiates energy in all directions.

Explanation:

Most of it dissipates into space, but the tiny fraction of the sun's energy that reaches Earth is enough to heat the planet and drive the global weather system by warming the atmosphere and oceans

3 0
3 years ago
(h) The student made observations related to the contents of the Erlenmeyer flask during the titration. Identify an observation
katen-ka-za [31]

Answer:

Explanation:

During titration indicators are often used to identify chemical changes between reacting species.

For colorless solutions in which no noticeable changes can easily be seen, indicators are the best bet. Most titration processes involves a combination of acids and bases to an end point.

Indicators are substances whose color changes to signal the end of an acid-base reaction. Examples are methyl orange, methyl red, phenolphthalein, litmus, cresol red, cresol green, alizarin R3, bromothymol blue and congo red.

Most of these indicators have various colors when chemical changes occur.

Also, there are heat changes that accompanies most of these reactions. These are also indicators of chemical changes.

5 0
3 years ago
You are requested to reduce the size of 50 ton/hr of a given solid. The size of the feed is such 80% passes a 4-in (76.2 mm) scr
defon

Answer:

1) The power needed to process 50 ton/hr is 135.4 HP.

2) The void fraction of the bed is 0.37.

Explanation:

1) For this type of milling operations, we can estimate the power needed for an operation according to the work index (Ei), the passing size of the circuit feed (F80) and the passing size of the product (P80).

We assume the units of Ei are kWh/t.

The equation that relates this parameters and the power is (size of particles in μm):

W=Ei*(\frac{10}{\sqrt{P80}} -\frac{10}{\sqrt{F80}} )\\\\W=9.45*(\frac{10}{\sqrt{3175\mu m}} -\frac{10}{\sqrt{76200mm}} )\\\\\\W=9.45*(0.1774+0.0362)=2.019 kWh/t

The power needed to process 50 ton/hor is

P=2.0194\frac{kWh}{Ton}*\frac{50Ton}{h}*\frac{1.341HP}{1kW}=   135.4 \, HP

2) The density of the packed bed can be expressed as

\rho=f_v*\rho_v+f_s*\rho_s

being f the fraction and ρ the density of every fraction. We know that the density of the void is 0 (ρv=0) and that fv=1-fs (the sum  of the fractions ois equal to the total space).

Then we can rearrange

\rho=f_v*\rho_v+f_s*\rho_s\\\\\rho=f_v*0+(1-f_v)*\rho_s\\\\\rho/\rho_s=1-f_v\\\\f_v=1-\rho/\rho_s=1-990/1570=1-0.63=0.37

The void fraction of the bed is 0.37.

6 0
3 years ago
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