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dimaraw [331]
3 years ago
12

In the chemical closet, you found an unlabeled vial with a solid piece of an unknown element inside (element Z) You decided to p

ut it in the mass-spec to figure out its atomic mass. The results showed that it has two naturally occurring isotopes, Z-85, and Z-87. Z-85 has a natural abundance of 72.17% and a mass of 84 912 amu Z-87 has a natural abundance of 27 83% and a mass of 86 909 amu. Calculate the average atomic mass and determine the identity of mystery element Z
Chemistry
1 answer:
-BARSIC- [3]3 years ago
6 0

Answer:

85.4678

It is Rubidium

Explanation:

A natural abundance of 72.17% and a mass of 84 912 amu

A natural abundance of 27 83% and a mass of 86 909 amu.

Average atomic mass

= 84.912 x .7217 + 86.909 x .2783

= 61.28099+24.18677

= 85.46776

=85.4678

It is Rubidium .

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Picture attached, $3
Luba_88 [7]

Answer:

its -000.5

Explanation:

6 0
3 years ago
You need to prepare at 2.0 mL sample of a diluted drug for injection. The total amount of the drug to be injected in this 2.0 mL
pav-90 [236]

Answer:

a) The concentration of drug in the bottle is 9.8 mg/ml

b) 0.15 ml drug solution + 1.85 ml saline.

c) 4.9 × 10⁻⁵ mol/l

Explanation:

Hi there!

a) The concentration of the drug in the bottle is 294 mg/ 30.0 ml = 9.8 mg/ml

b) The drug has to be administrated at a dose of 0.0210 mg/ kg body mass. Then, the total mass of drug that there should be in the injection for a person of 70 kg will be:

0.0210 mg/kg-body mass * 70 kg = 1.47 mg drug.

The volume of solution that contains that mass of drug can be calculated using the value of the concentration calculated in a)

If 9.8 mg of the drug is contained in 1 ml of solution, then 1.47 mg drug will be present in (1.47 mg * 1 ml/ 9.8 mg) 0.15 ml.

To prepare the injection, you should take 0.15 ml of the concentrated drug solution and (2.0 ml - 0.15 ml) 1.85 ml saline

c) In the injection there is a concentration of (1.47 mg / 2.0 ml) 0.735 mg/ml.

Let´s convert it to molarity:

0.735 mg/ml * 1000 ml/l * 0.001 g/mg* 1 mol/ 15000 g = 4.9 × 10⁻⁵ mol/l

3 0
3 years ago
Storing sugar as long chains for later use is an example of a(n) ____________ chemical reaction.
DerKrebs [107]

Answer:

Endothermic

Explanation:

Storing sugar for later use is an example of an endothermic reaction because that energy is being absorbed.

8 0
3 years ago
What is the gcf of 16 and 72? <br> a. 2 <br> b. 4 <br> c. 16 <br> d. 8
nadya68 [22]
Your answer is D. 8

16 = 2^4
72 = 2^3*3^2

So you'll choose 2^3 = 8
7 0
3 years ago
Read 2 more answers
Under identical conditions of temperature and pressure, which of the following gasses is the densest: Ne, CO2, or Cl2?
Tanzania [10]
Cl2=3.17g/L
Ne=.901g/L
CO2=1.96g/l
 therefore Cl2 is the densest gas under the given conditions.
7 0
2 years ago
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