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dimaraw [331]
4 years ago
12

In the chemical closet, you found an unlabeled vial with a solid piece of an unknown element inside (element Z) You decided to p

ut it in the mass-spec to figure out its atomic mass. The results showed that it has two naturally occurring isotopes, Z-85, and Z-87. Z-85 has a natural abundance of 72.17% and a mass of 84 912 amu Z-87 has a natural abundance of 27 83% and a mass of 86 909 amu. Calculate the average atomic mass and determine the identity of mystery element Z
Chemistry
1 answer:
-BARSIC- [3]4 years ago
6 0

Answer:

85.4678

It is Rubidium

Explanation:

A natural abundance of 72.17% and a mass of 84 912 amu

A natural abundance of 27 83% and a mass of 86 909 amu.

Average atomic mass

= 84.912 x .7217 + 86.909 x .2783

= 61.28099+24.18677

= 85.46776

=85.4678

It is Rubidium .

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<h3>What is the pressure of the Nitrogen gas?</h3>

The pressure of the nitrogen gas is determined from ideal gas equation, as shown below;

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2 years ago
Which of the following statements is true regarding bacteria and animal cells?
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Explanation:

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