Answer:
Total volume is 625 mL
Explanation:
We use the 6 % (m/v) data which is a sort of concentration. This percent means that the solution has 6 g of solute in 100 mL of solution
So we make a rule of three:
6 g of solute (NaCl) are in 100 mL of solution
Therefore, 37.5 g are in (37.5 .100) / 6 = 625 mL
Answer:
ΔH3 = -110.5 kJ.
Explanation:
Hello!
In this case, by using the Hess Law, we can manipulate the given equation to obtain the combustion of C to CO as shown below:
C(s) + 1/2O2(g) --> CO(g)
Thus, by letting the first reaction to be unchanged:
C(s) + O2(g)--> CO2 (g) ; ΔH1 = -393.5 kJ
And the second one inverted:
CO2(g) --> CO(g) + 1/2O2(g) ; ΔH2= 283.0kJ
If we add them, we obtain:
C(s) + O2(g) + CO2(g) --> CO(g) + CO2 (g) + 1/2O2(g)
Whereas CO2 can be cancelled out and O2 subtracted:
C(s) + 1/2O2(g) --> CO(g)
Therefore, the required enthalpy of reaction is:
ΔH3 = -393.5 kJ + 283.0kJ
ΔH3 = -110.5 kJ
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Answer: Laws have been passed banning the production of a living copy of a person.
i just took the test so i know the answer is correct.
Answer:
D.A high temperature will make it spontaneous.
Explanation:
we know that
Δ G = Δ H - TΔS
For spontaneous reaction
Δ G should be negative . If Δ G = 0
Δ H = TΔS
T = Δ H / Δ S
At temperature above this T , Δ G becomes negative if Δ S and ΔH are positive .
So at a high temperature will make it spontaneous.
Answer: 2
Explanation: The equation needs to be balanced in order for the law of conservation of mass to be applied.