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3 years ago

Can a real refrigerator have higher COP than the COP of the Carnot refrigerator?

Engineering

2 answers:

astra-53 [7]3 years ago

5 0

Answer:

Explanation:

As we know that Carnot refrigerator is an ideal refrigerator in which all processes are reversible and COP of refrigerator depends only on temperature limit of evaporator and condenser.

On the other hand a real refrigerator consist irreversibility that is why the COP of real refrigerator is less that Carnot refrigerator.

So we can say that COP of Carnot refrigerator is always more that COP of real refrigerator.

Flauer [41]3 years ago

4 0

Answer: NO

Explanation:

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3 years ago

What is differences Between hard shoulder & soft shoulder in civil Engineerin?

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4 years ago

Given a force of 72 lbs at a distance of 15 ft, calculate the moment produced.

Elis [28]

Answer:

1425.78 N.m

Explanation:

Moments of force is calculated as ;

Moments= Force * distance

M= F*d

The S.I unit for moment of force is Newton-meter (N.m)

Given in the question;

Force = 72 lbs

1 pound = 4.45 N

72 lbs = 4.45 * 72=320.4 N

Distance= 15 ft

1ft= 0.3048 m

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4 years ago

You have an ac voltage of 10 sin(60t). Design a full wave bridge rectifier which will give you an output voltage that varies a m

Masteriza [31]

As there are 10 V, for Vp1, that is the peak-voltage of the source:

$Vp1=10*\sqrt{2}=14.14 V$

Then, transformer's theory says that the relation of transformations is:

V1/V2=a

Where V1 is the voltage in the primary and V2 in the secondary.

V1=14.14 V

V2=8.55 V

a=1.65

Then, with the 8.5 V, we find the real peak-voltage, taking in account that in the diodes we have a drop of 0.7 V each, so:

8.5 -1.4=7.1 V

And this will be called VpL

Now we proceed to calculate the mean voltage:

$V_{mean}=VpL-(\frac{Vr}{2} )$

Where Vr is the ripple voltage, we asume that is 1 V

So, Vmean = 6.6 V

Then we have

Vmean/R= I mean

We have that R=1000 Ohm

Imedia=6.6 V/1000 Ohm

Imedia=6.6 mAmps

Finally, we can calculate the capacitor:

C=Q/Vr

C=Imean/(Vr*2f)

Where f is 60Hz

C=6.6mA/(1V*120)

C=5.5 uFarads

Therefore:

C=5.5 uFarads that works at 12 V

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3 years ago