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Varvara68 [4.7K]
3 years ago
7

Can a real refrigerator have higher COP than the COP of the Carnot refrigerator?

Engineering
2 answers:
astra-53 [7]3 years ago
5 0

Answer:

No

Explanation:

As we know that Carnot refrigerator is an ideal refrigerator in which all processes are reversible and COP of refrigerator depends only on temperature limit of evaporator and condenser.

On the other hand a real refrigerator consist irreversibility that is why the COP of real refrigerator is less that Carnot refrigerator.

So we can say that COP of Carnot  refrigerator is always more that COP of  real refrigerator.

Flauer [41]3 years ago
4 0

Answer: NO

Explanation:

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Answer:

  248.756 mV

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Explanation:

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  voltage = (100 V)(1010/(1000 +1010) = 100(101/201) ≈ 50 50/201 V

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mixas84 [53]

Answer:

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Explanation:

Attached below is a schematic representation of the solution

<u>a) Identify the variables in the solution vector assume Bus 2 is a load bus</u>

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<em>Hence the variables in the solution </em>

<em>= | v2 | ,  β2   ( load, bus voltage at bus 2 )</em>

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specified parameter : | v1 |  and β1

unspecified : p1 and q1

<em>Hence the variables in the solution </em>

<em>= q2 , β2  </em>

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The tax on this property is 3750 dollars

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3 years ago
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