A 254 kg motorcycle moves with a velocity of 3 m/s. What is its kinetic energy?
1 answer:
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Answer:
F = 2.49 x 10⁻⁹ N
Explanation:
The electrostatic force between two charged bodies is given by Colomb's Law:
where,
F = Electrostatic Force = ?
k = colomb's constant = 9 x 10⁹ N.m²/C²
q₁ = charge on proton = 1.6 x 10⁻¹⁹ C
q₂ = second charge = 1.4 C
r = distace between charges = 0.9 m
Therefore,
<u>F = 2.49 x 10⁻⁹ N</u>
Answer:
6.0 × W/
Explanation:
From Wien's displacement formula;
Q = e A
Where: Q is the quantity of heat transferred, e is the emissivity of the surface, A is the area, and T is the temperature.
The emissive intensity = = e
Given from the question that: e = 0.6 and T = 1000K, thus;
emissive intensity = 0.6 ×
= 0.6 × 1.0 ×
= 6.0 ×
Therefore, the emissive intensity coming out of the surface is 6.0 × W/
.