Answer:
Explanation:
C = 6 x 10^-6 F, V = 12 V,
Energy stored in the capacitor
E = 1/2 CV^2 = 0.5 x 6 x 10^-6 x 12 x 12 = 4.32 x 10^-4 J
Now the voltage is 6 V, So let energy be E'
E' = 1/2 CV^2 = 0.5 x 6 x 10^-6 x 6 x 6 = 1.08 x 10^-4 J
The energy stored in a capacitor is proportional to the square of teh potential difference applied across the capacitor.
Answer:
Yes, the battery's store of chemical potential energy will have decreased. Work is done on the positive charge in moving that charge to the battery's positive terminal. Chemical potential energy is converted into electrostatic potential energy in pushing the positive charge up a voltage gradient. Hope this helps!
Explanation:
False because their are ethical boundaries that prevent full range of scientific research.
V = 0, a increasing
a = 0
v increasing, a increasing
v decreasing, a decreasing
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