3 years ago

A mass m = 4.6 kg hangs on the end of a massless rope L = 2.16 m long. The pendulum is held horizontal and released from rest.

1 answer:

4 0

ind the velocity my using the conservation of energy mgh=1/2mv^2. At the bottom, the mass is turning in a circle with tension pointing up towards the center of the circle and weight pointing down. Use the centripetal force requirement mv^2/r=T-W and solve for T. Hope this helps.

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If the work done to stretch an ideal spring by 4.0 cm is 6.0 J, what is the spring constant (force constant) of this spring? A)

Ostrovityanka [42]

Answer:

D) 7500 N/m

Explanation:

Given :

Work done by the spring, W = 6 J

Stretch in the spring, x = 4 cm = 0.04 m

Consider k be the spring constant.

The relation between work done and stretch of the spring is:

$W=\frac{1}{2}kx^{2}$