Given:
P1 = 13.0 atm
T1 = 20 °C
T2 = 102 °C
Required:
P2 of oxygen
Solution:
At constant volume,
we can apply Gay-Lussac’s law of pressure and temperature relationship
P1/T1=P2/T2
(13.0 atm) / (20 °C)
= P2 / (102 °C)
P2 = 66.3 atm
The answer is not in the choices given.
The type of reaction in the example below is a double replacement.
A double replacement can be identified by the switch between two reactants. This can be verified because both a Br and Cl are being switched to a new position in the reaction.
Explanation:
Lead(II) phosphate is an ionic compound with chemical formula Pb3(PO4)2. Lead(II) phosphate is a long-lived electronically neutral reagent chemical.[1] Despite limited tests on humans, it has been identified as a carcinogen based on tests on animals conducted by the EPA.[2] Lead(II) phosphate appears as hexagonal, colorless crystals or as a white powder. Lead(II) phosphate is insoluble in water and alcohol but soluble in Nitric acid (HNO3) and has fixed alkali hydroxides. When lead(II) phosphate is heated for decomposition it emits very toxic fumes containing Lead (Pb) and POx.[3]
3 moles of NaOH reacts with 1 mole of phosphoric acid.
<h3>What is the moles ratio of the NaOH and Phosphoric acid reaction?</h3>
The moles ratio of the reaction between NaOH and Phosphoric acid is given by the equation of the reaction below:
Based on the equation of the reaction, 3 moles of NaOH reacts with 1 mole of phosphoric acid.
Learn more about mole ratio at: brainly.com/question/19099163
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