During welding in the vertical position, the torch angle can be varied to control sagging.

Determine the depreciation expense for 2018 and 2019 using the following methods: (a) Straight-line (SL), (b) Units of produc

prohojiy [21]

Answer:

Check Explanation.

Explanation:

(1). The straight-line method: the general clue with this method is that in the two years, depreciation is the same. The formula for Calculating depreciation is given below;

straight-line method = (cost - Residual value)/ useful life in years.

From the question we know that the cost of acquisition is $30,000,000, the residual value of the asset is $4,000,000 and useful life is 7 years. Therefore;

straight-line method = ($30,000,000 - $4,000,000)/ 7.

= $3, 714,285.71 Per year.

That is $3, 714,285.71 for 2018 and 2019.

(2).Units of production (UOP) = (cost - Residual value)/ useful life in units.

= ($30,000,000 - $4,000,000)/ 4,375, 000.

Units of production (UOP) = $6 per mile.

Hence, the depreciation in 2018 = Depreciation per unit × 2018 year usage.

= 6 × 1,100,000 mile.

= $6,600,000.

depreciation in 2019 = Depreciation per unit × 2019 year usage.

= 6 × 1,200,000.

= $7,200,000.

Double-declining-balance (DDB)= (cost - accumulated depreciation) × 2 × 1/(useful life years).

Double-declining-balance (DDB) = (30,000,000 - 0)× 2 × (1/7).

= $8,571,428.57 depreciation in 2018.

= $8,571,428.6 depreciation in 2018

Double-declining-balance (DDB) = (30,000,000 - 8,571,428.57) × 2 × 1/7.

= $6,122,449.00 depreciation in 2019.

====================================================================

Total depreciation for straight-line method(2018 and 2019) = $7,428,571.42.

Total depreciation for Units of production (UOP)(2018 and 2019) = $13,800,000.

Total depreciation for Double-declining-balance (DDB)= $ 14,693,877.6.

5 0

3 years ago

Calculate the reluctance of a 4-meter long toroidal coil made of low-carbon steel with an inner radius of 1.75 cm and an outer r

My name is Ann [436]

Answer:

R = 31.9 x 10^(6) At/Wb

So option A is correct

Explanation:

Reluctance is obtained by dividing the length of the magnetic path L by the permeability times the cross-sectional area A

Thus; R = L/μA,

Now from the question,

L = 4m

r_1 = 1.75cm = 0.0175m

r_2 = 2.2cm = 0.022m

So Area will be A_2 - A_1

Thus = π(r_2)² - π(r_1)²

A = π(0.0225)² - π(0.0175)²

A = π[0.0002]

A = 6.28 x 10^(-4) m²

We are given that;

L = 4m

μ_steel = 2 x 10^(-4) Wb/At - m

Thus, reluctance is calculated as;

R = 4/(2 x 10^(-4) x 6.28x 10^(-4))

R = 0.319 x 10^(8) At/Wb

R = 31.9 x 10^(6) At/Wb

8 0

4 years ago

I need help on what’s and input and output to make the flowchart

e-lub [12.9K]

Input: what is put in, taken in, or operated on by any process or system.

Output: the amount of something produced by a person, machine, or industry.

3 0

3 years ago

A) Fix any errors to get the following program to run in your environment. B) Document each line of code with comments and descr

Bingel [31]

Answer:

Answer is explained below

Explanation:

Part A -:

Error statement -:

/*

prog.cpp: In function ‘void p(const int*, int)’:

prog.cpp:7:15: error: assignment of read-only location ‘* list’

list[0] = 100;

*/

There is one error in the code in following part

void p( const int list[], int arraySize)

{

list[0] = 100;

}

you are passing list as constant but changing it inside the function that is not allowed. if you pass any argument as const then you can't change it inside the function. so remove const from function argument solve the error.

Part B -:

change made

void p( int list[], int arraySize)

{

list[0] = 100;

}

Executable fully commented code -: 

#include <iostream> // importing the iostream library

using namespace std;

void m(int, int []); // Function declearation of m

void p( int list[], int arraySize) // definition of Function p

{

list[0] = 100; // making value of first element of list as 100

}

int main()

{

int x = 1; // initilizing x with 1

int y[10]; // y is a array of 10 elements

y[0] = 1; // first element of y array is 1

m(x, y); // call m function

// printing the desired result

cout << "x is " << x << endl;

cout << "y[0] is " << y[0] << endl;

return 0;

}

void m(int number, int numbers[]) // Function definition of m

{

number = 1001; // value of number is 1001 locally

numbers[0] = 5555; // making value of first element of numbers array 5555

}

Part C :-

In program we initilize x with value 1 and create an array y of 10 elements.

we initilize the y[0] with 1\

then we call function m. In function m ,first argument is value of x and second argument is the pointer to the first element of array y.

so value of x is changed locally in function m and change is not reflected in main function.

but value of y[0] is changed to 5555 because of pass by refrence.

So we are getting the following result :-

x is 1

y[0] is 5555

4 0

3 years ago

16 engineering design process

Nesterboy [21]

Answer:

iejf go jjflkkkfffnfb ffv jedj HD video for my homework and I will be

Explanation:

for my homework and I will bemdjdjhdghy get a chance to look at the calendar please find my attached updatedg my homework and I will be there at the same time I will be thereg my homework and I need

6 0

3 years ago