The trip from Camp Wood to the Pacific
Ocean and back again took 1.5 years to complete.<span>
</span>
<span>The </span>Lewis<span> and Clark </span>Expedition<span> from May 1804 to September 1806, also known as
the Corps of Discovery </span>Expedition, was the first
American expedition<span> to
cross what is now the western portion of the United States.</span>
speed of the car = 27 m/s
speed of truck ahead = 10 m/s
relative speed of car with respect to truck
relative deceleration of car
now the distance before they stop with respect to each other is given by
so it will come at the same speed of truck after 20.6 m distance and hence it will not hit the truck as the distance of the truck is 25 m from car
Part b)
Distance traveled by car before it stops is given by
so it will stop after it will cover total 52.1 m distance
Part c)
time taken by the car to stop
now the distance covered by truck in same time
now after the car will stop its distance from the truck is
<em>so the distance between them is 11.5 m</em>
Answer:
A. 1.172 metres
B. 6.82 Ns
C. 4.796 m/s
Explanation:
The total initial momentum is gotten by multiplying the mass and initial velocity of the both bodies.
The 1.40 kg block is at rest so velocity is zero and has no momentum.
The bullet of mass 22 g = 0.022 kg with velocity of 310 m/s
Momentum = 310*0.022
Momentum = 6.82 Ns.
If the bullet gets embedded they will both have common velocity v
6.82 = (0.022+1.40)v
6.82 = 1.422v
V = 6.82/1.422
V = 4.796 m/s
How high the block will rise after the bullet is embedded is given by
H = (U²Sin²tita)/2g
Where tita is 90°
H = (4.796² * sin²(90))/(2*9.81)
H =( 23.001616*1)/19.62
H = 1.172 metres
Umm... I think I saw this question somewhere else answered.... You should look for it.
