All categories

3 years ago

Give the approximate temperature at which creep deformation becomes an important consideration for each of the following metals:

Engineering

1 answer:

IrinaVladis [17]3 years ago

8 0

Answer:

The creep temperature for different materials is as follows.

A. Nickel :- $T_{c}$ = 690.4 K

B. Copper :- $T_{c}$ = 542.8 K

C. Iron :- $T_{c}$ = 723.6 K

D. Tungsten :- $T_{c}$ = 1469.2 K

E. Lead :- $T_{c}$ = 240.2 K

F. Aluminium :- $T_{c}$ = 373.2 K

Explanation:

Creep is the slow plastic deformation occur at high elevated temperature.

The approximate temperature for different metals is as follows at which creep becomes considerable.

A. Nickel :- The relation between melting temperature & creep temperature is given by the formula.

$T_{c} = 0.4 T_{m}$

The melting temperature of nickel = 1726 K

Creep temperature $T_{c}$ = 0.4 × 1726

$T_{c}$ = 690.4 K

B. Copper :- The relation between melting temperature & creep temperature for copper is given by the formula.

$T_{c} = 0.4 T_{m}$

The melting temperature of copper = 1357 K

Creep temperature $T_{c}$ = 0.4 × 1357

$T_{c}$ = 542.8 K

C. Iron :- The relation between melting temperature & creep temperature for iron is given by the formula

$T_{c} = 0.4 T_{m}$

The melting temperature of iron = 1809 K

Creep temperature $T_{c}$ = 0.4 × 1809

$T_{c}$ = 723.6 K

D. Tungsten :- The relation between melting temperature & creep temperature for tungsten is given by the formula

$T_{c} = 0.4 T_{m}$

The melting temperature of iron = 3673 K

Creep temperature $T_{c}$ = 0.4 × 3673

$T_{c}$ = 1469.2 K

E. Lead :-The relation between melting temperature & creep temperature for lead is given by the formula

$T_{c} = 0.4 T_{m}$

The melting temperature of lead = 600.5 K

Creep temperature $T_{c}$ = 0.4 × 600.5

$T_{c}$ = 240.2 K

F. Aluminium :- The relation between melting temperature & creep temperature for aluminium is given by the formula

$T_{c} = 0.4 T_{m}$

The melting temperature of lead = 933 K

Creep temperature $T_{c}$ = 0.4 × 933

$T_{c}$ = 373.2 K

You might be interested in

Help please its due today will mark you brainliest

Tems11 [23]

Answer:

launch- The first stage is ignited at launch and burns through the powered ascent until its propellants are exhausted. The first stage engine is then extinguished, the second stage separates from the first stage, and the second stage engine is ignited. The payload is carried atop the second stage into orbit

powered ascent-The first stage is ignited at launch and burns through the powered ascent until its propellants are exhausted. The first stage engine is then extinguished, the second stage separates from the first stage, and the second stage engine is ignited. The payload is carried atop the second stage into orbit

coasting flight-

When the rocket runs out of fuel, it enters a coasting flight. The vehicle slows down under the action of the weight and drag since there is no longer any thrust present. The rocket eventually reaches some maximum altitude which you can measure using some simple length and angle measurements and trigonometry.

ejection charge-At the end of the delay charge, an ejection charge is ignited which pressurizes the body tube, blows the nose cap off, and deploys the parachute. The rocket then begins a slow descent under parachute to a recovery. The forces at work here are the weight of the vehicle and the drag of the parachute.

slow decent- slow downs (i guess)

recovery-A recovery period is typically characterized by abnormally high levels of growth in real gross domestic product, employment, corporate profits, and other indicators. This is a turning point from contraction to expansion and often results in an increase in consumer confidence

Explanation:

6 0

4 years ago

Which of the following is most useful for doing research?

Ghella [55]

Answer:

Web Browser

Explanation:

Because you dont use a messaging app or presentation software to look up stuff its common knowledge

7 0

3 years ago

. En la facultad de Ingeniería Industrial se realizó una encuesta a 200 personas para saber que lenguaje de programación preferí

GarryVolchara [31]

Answer:

lalalalapumpe

Explanation:

4 0

3 years ago

Water vapor at 10bar, 360°C enters a turbine operatingat steady state with a volumetric flow rate of 0.8m3/s and expandsadiabati

Artyom0805 [142]

Answer:

A) W' = 178.568 KW

B) ΔS = 2.6367 KW/k

C) η = 0.3

Explanation:

We are given;

Temperature at state 1;T1 = 360 °C

Temperature at state 2;T2 = 160 °C

Pressure at state 1;P1 = 10 bar

Pressure at State 2;P2 = 1 bar

Volumetric flow rate;V' = 0.8 m³/s

A) From table A-6 attached and by interpolation at temperature of 360°C and Pressure of 10 bar, we have;

Specific volume;v1 = 0.287322 m³/kg

Mass flow rate of water vapour at turbine is defined by the formula;

m' = V'/v1

So; m' = 0.8/0.287322

m' = 2.784 kg/s

Now, From table A-6 attached and by interpolation at state 1 with temperature of 360°C and Pressure of 10 bar, we have;

Specific enthalpy;h1 = 3179.46 KJ/kg

Now, From table A-6 attached and by interpolation at state 2 with temperature of 160°C and Pressure of 1 bar, we have;

Specific enthalpy;h2 = 3115.32 KJ/kg

Now, since stray heat transfer is neglected at turbine, we have;

-W' = m'[(h2 - h1) + ((V2)² - (V1)²)/2 + g(z2 - z1)]

Potential and kinetic energy can be neglected and so we have;

-W' = m'(h2 - h1)

Plugging in relevant values, the work of the turbine is;

W' = -2.784(3115.32 - 3179.46)

W' = 178.568 KW

B) Still From table A-6 attached and by interpolation at state 1 with temperature of 360°C and Pressure of 10 bar, we have;

Specific entropy: s1 = 7.3357 KJ/Kg.k

Still from table A-6 attached and by interpolation at state 2 with temperature of 160°C and Pressure of 1 bar, we have;

Specific entropy; s2 = 8.2828 KJ/kg.k

The amount of entropy produced is defined by;

ΔS = m'(s2 - s1)

ΔS = 2.784(8.2828 - 7.3357)

ΔS = 2.6367 KW/k

C) Still from table A-6 attached and by interpolation at state 2 with s2 = s2s = 8.2828 KJ/kg.k and Pressure of 1 bar, we have;

h2s = 2966.14 KJ/Kg

Energy equation for turbine at ideal process is defined as;

Q' - W' = m'[(h2 - h1) + ((V2)² - (V1)²)/2 + g(z2 - z1)]

Again, Potential and kinetic energy can be neglected and so we have;

-W' = m'(h2s - h1)

W' = -2.784(2966.14 - 3179.46)

W' = 593.88 KW

the isentropic turbine efficiency is defined as;

η = W_actual/W_ideal

η = 178.568/593.88 = 0.3

8 0

3 years ago

A manometer is used to measure the air pressure in a tanlc The fluid used has a specific gravity of 1.25, and the differentialhe

Alenkasestr [34]

Answer:

(a) 11.437 psia

(b) 13.963 psia

Explanation:

The pressure exerted by a fluid can be estimated by multiplying the density of the fluid, acceleration due to gravity and the depth of the fluid. To determine the fluid density, we have:

fluid density = specific gravity * density of water = 1.25 * 62.4 lbm/ft^3 = 78 lbm/ft^3

height = 28 in * (1 ft/12 in) = 2.33 ft

acceleration due to gravity = 32.174 ft/s^2

The change in pressure = fluid density*acceleration due to gravity*height = 78*32.174*(28/12) = 5855.668 lbm*ft/(s^2 * ft^2) = 5855.668 lbf/ft^2

The we convert from lbf/ft^2 to psi:

(5855.668/32.174)*0.00694 psi = 1.263 psi

(a) pressure = atmospheric pressure - change in pressure = 12.7 - 1.263 = 11.437 psia

(b) pressure = atmospheric pressure + change in pressure = 12.7 + 1.263 = 13.963 psia

8 0

3 years ago