If we integrate dx/dt we get x, which is the number of calculators. To find the number of calculators between the beginning of third week to the end of fourth week (the beginning of fifth week), this integration must be evaluated at t between 3 and 5.

$x=\int\limits^5_3 {\frac{dx}{dt}} \, dt =\int\limits^5_3 {5000(1-\frac{100}{(t+10)^2})} \, dt$

the result of the integration is:

$x=5000(t+\frac{100}{t+10})$ to be evaluated between 3 and 5, which is:

$x=5000(5+\frac{100}{5+10})-5000(3+\frac{100}{3+10})=\frac{190000}{39}=4871.8$

6 0

3 years ago

The jogger can run at an average speed of 5.5 miles per hour up the slope and 6.5 miles per hour going down the slope. The jogge

Bond [772]

<span>DOC]<span>Venn Diagram Task – Differentiation - Summer Summit

paste that into google and the last page is the answer sheet</span></span>

7 0

3 years ago