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Anarel [89]
3 years ago
5

When NaCl dissolves in water, aqueous Na+ and Cl- ions result. The force of attraction that exists between Na+ and H2O is called

a(n) __________ interaction. Select one: a. dipole-dipole b. ion-ion c. hydrogen bonding d. ion-dipole e. London dispersion force
Chemistry
1 answer:
kiruha [24]3 years ago
4 0

Answer:

b. ion-ion

Explanation:

When NaCl dissolves in water , it dissociates completely into the corresponding ions , i.e. , Na⁺ and Cl⁻ ,

Since , the charges have complete positive and negative charges , hence , they interact with each other via ion - ion interaction , i.e. the interaction between the positive and negative charges , is referred to as ion - ion interaction .

Hence , the correct option is b. ion-ion interaction .

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Which of the following flows is not driven by pressure differences?
AlekseyPX

Answer:

I think it is option (b) river

7 0
3 years ago
32.7 grams of water vapor takes up how many liters at standard temperature and pressure (273 K and 100 kPa)?
kotegsom [21]
Under standard temperature and pressure conditions, it is known that 1 mole of a gas occupies 22.4 liters.

From the periodic table:
molar mass of oxygen = 16 gm
molar mass of hydrogen = 1 gm
Thus, the molar mass of water vapor = 2(1) + 16 = 18 gm

18 gm of water occupies 22.4 liters, therefore:
volume occupied by 32.7 gm = (32.7 x 22.4) / 18 = 40.6933 liters

5 0
3 years ago
An object has a mass of 20 g and a volume of 5 mL what is the objects density
IceJOKER [234]
<span>4000 kilogram/cubic meter
http://www.calculator.net/density-calculator.html?cdensity=&cdensityunit=kilogram%2Fcubic+meter&cvol...
</span>
7 0
3 years ago
a balloon contains 30.0 L of helium gas at 103 kPA. what is the volume of the helium when the balloon rises to an altitude where
stiv31 [10]
Answer:
                V₂  =  123.6 L

Explanation:

According to Boyle's law pressure and volume of a gas are inversely related if amount and temperature are kept constant. For the initial and final states the gas law is given as,

                                                P₁ V₁  =  P₂ V₂     ----- (1)
Data Given;
                   P₁  =  103 kPa

                   V₁  =  30 L

                   P₂  =  25 kPa

                   V₂  =  ?

Solution:

Solving equation 1 for V₂,

                                        V₂  =  P₁ V₁ / P₂

Putting values,
                                        V₂  =  (103 kPa × 30 L) ÷ 25 kPa

                                        V₂  =  123.6 L

Result:
           As the pressure is decreased from 103 kPa to 25 kPa, therefore, volume has increased from 30 L to 123.6 L.
8 0
3 years ago
List 3 examples of elements
KiRa [710]
Aluminum, Carbon, Cobalt, Copper, Zinc, Tantalum
3 0
4 years ago
Read 2 more answers
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