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Zanzabum
3 years ago
14

A sample of Hydrogen gas has a volume of 25.5 liters at a pressure of 15.0 kPa. If the temperature is kept constant and the pres

sure is raised to 50.0 kPa, what is the new volume of the gas, in liters?
Chemistry
1 answer:
patriot [66]3 years ago
5 0

Answer:

<h2>7.65 litres </h2>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we're finding the new volume

V_2 =  \frac{P_1V_1}{P_2}  \\

15 kPa = 15,000 Pa

50 kPa = 50,000 Pa

We have

V_2 =  \frac{15000 \times 25.5}{50000}  =  \frac{382500}{50000}  \\  = 7.65

We have the final answer as

<h3>7.65 litres </h3>

Hope this helps you

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Which of the following happens when an ionic bond is formed? (1 point)
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This problem is asking for an explanation of what happens when an ionic bond is formed. Although the choices are not given in the question, one can find them on the attached file and realize the answer is C "a less electronegative atom donates an electron to a more electronegative atom" according to:

<h3>Types of bonds:</h3><h3 />

In chemistry, the forces that hold atoms together are known as chemical bonds and act like connections for atoms to form compounds. There exist ionic and covalent bonds, so the formers occur when electrons are thoroughly donated from the least electronegative atom to the most electronegative one.

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4 years ago
Based on the context of paragraph 4, what are salient factors?
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Read 2 more answers
PLEASE HELP!
Tanzania [10]
Molar mass:

KCl = 74.55 g/mol

KClO3 = 122. 55 g/mol

  <span>Calculation of the mass of KClO3 :</span>

<span>2 KClO3 =  2 KCl + 3 O2</span>

2* 122.55 g KClO3 ------------------ 2 * 74.55 g KCl
mass KClO3 ?? --------------------- 25.6 g KCl

mass KClO3 = 25.6 * 2 * 122.55 / 2 * 74.55

mass KClO3 = 6274.56 / 149.1

mass = 42.082 g of  KClO3

Therefore:

1 mole KClO3 ---------------------- 122.55 g
?? moles KClO3 ------------------- 42.082 g

moles KClO3 = 42.082 * 1 / 122.55

moles KClO3 = 42.082 / 122.55

=> 0.343 moles of KClO3


Answer C

hope this helps!

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