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patriot [66]
4 years ago
10

A particle is moving around in a circle and its position is given in polar coordinates as x = Rcosθ, and y = Rsinθ, where R is t

he radius of the circle, and θ is in radians. From these equations derive the equation for centripetal acceleration.
Physics
1 answer:
yaroslaw [1]4 years ago
3 0

“Without loss of generality, we only need to look at the equation for the x-position, since we know that centripetal acceleration points towards the center of the circle. Thus, when θ = 0, the second derivative of x with respect to time must be the centripetal acceleration.


The first derivative of x with respect to time t is:


dx/dt = —Rsinθ(dθ/dt)


The second derivative of x with respect to time t is:


d2x/dt2 = —Rcosθ(dθ/dt)2—Rsinθ(d2θ/dt2)


In both of the above equations the chain rule of Calculus is used and by assumption θ is a function of time. Therefore, θ can be differentiated with respect to time.


Now, evaluate the second derivative at θ = 0.


We have,


d2x/dt2 = —R(dθ/dt)2


The term dθ/dt is usually called the angular velocity, which is the rate of change of the angle θ. It has units of radians/second.


For convenience we can set w ≡ dθ/dt.


Therefore,


d2x/dt2 = —Rw2


This is the well-known form for the centripetal acceleration equation.”

-Leah

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