If you have a ream of notebook paper available, you can measure the height of the stack and divide that by the number of sheets in the ream.
Or you can look up the average density of notebook paper, measure the mass of the sheet, then find the volume by dividing its mass by its density. Then divide the volume by the length and width of the sheet.
Answer:
Optical fibers are used most often as a means to transmit light between the two ends of the fiber and find wide usage in fiber-optic communications, where they permit transmission over longer distances and at higher bandwidths (data rates) than wire cables.
Explanation:
Answer:
The marble at its highest point are hmax= 1.39 meters above the floor.
Explanation:
hi= 1m
V= 3m/s
Vx= 1.1 m/s
Vy= ?
α=cos⁻¹(1.1/3)
α= 68.48º
Vy= V * sin(α)
Vy= 2.79 m/s
Vertical Velocity in highest point are Vy(hmax) = 0
Vy(hmax)= Vy - g*t
t= Vy/g
t= 0.28 sec
t : time to get the highest point
hmax= hi + Vy*t - g*t²/2
hmax= 1.39 m
We can solve both parts of the problem by using the lens equation:
where
f is the focal length
is the distance of the object from the lens
is the distance of the image from the lens
Let's also keep in mind that for a converging lens, the focal length is taken as positive, so f=+19.0 cm.
(a) In this case,
. So, the lens equation becomes
And so the distance of the image from the lens is
where the positive sign means the image is real, i.e. is located behind the lens (opposite side of the real object)
(b) In this case,
. So, the lens equation becomes
And so the distance of the image from the lens is
where the negative sign means the image is virtual, i.e. is located in front of the lens (i.e. on the same side of the real object)
Answer:
A., B. & C.
Explanation:
All apply, because all these happen in a plant.