There's no info about the cars starting off differently, so as far as we know they have been side by side all the way.
<span>So from the last telephone pole: </span>
<span>(a) and (b): the displacement of both cars is 65.5m
the average speed for both car is 65.5m/5.0s = 13.1m/s</span>
-- You and your partner both get the same job to do:
Each of you gets a pallet of bricks, and you have to
put the bricks up on the bed of a truck, by hand.
Both pallets have the same number of bricks.
The pallet is way too heavy to lift, so you both cut the bands
that hold the bricks, and you lift the bricks from the pallet onto
the truck, by hand, two or three or four bricks at a time.
-- You get your pallet of bricks onto the truck in 45 minutes.
-- Your partner gets his pallet of bricks onto the truck in 3 days.
-- Work = (force) times (distance).
You and your partner both lifted the same amount of weight
up to the same height. You both did the same amount of work.
-- Power = (work done) divided by (time it takes to do the work) .
Your partner took roughly 96 times as long as you took
to do the same amount of work.
You did it faster. He did it slower.
You produced more power. He produced less power.
Answer:
The Reynolds numbers for flow in the fire hose.
Explanation:
Given that,
Diameter = 6.40 cm
Rate of flow = 40.0 L/s
Pressure 
We need to calculate the Reynolds numbers for flow in the fire hose
Using formula of rate of flow
Where, Q = rate of flow
A = area of cross section
Put the value into the formula
We need to calculate the Reynolds number
Using formula of the Reynolds number
Where, 
=viscosity of fluid
=density of fluid
Put the value into the formula
Hence, The Reynolds numbers for flow in the fire hose.
Answer:
25 m
Explanation:
Given:
v₀ = 10 m/s
v = 0 m/s
a = -2 m/s²
Find: Δx
v² = v₀² + 2aΔx
(0 m/s)² = (10 m/s)² + 2 (-2 m/s²) Δx
Δx = 25 m
