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ehidna [41]
3 years ago
13

Determined by the distance between objects and the difference in mass between the objects

Physics
2 answers:
emmasim [6.3K]3 years ago
8 0

Answer is gravitational force, according to e2020. Just took the review

lys-0071 [83]3 years ago
3 0
<span>Determined by the distance between objects and the difference in mass between the objects is gravity or gravitational force. Gravity is dependent on those two factors, and is what causes objects on Earth to stay on the ground. It is defined as the "pull" that an object with mass exerts on another object that makes the latter gravitate towards the former. Weight is the measure of gravitational force exerted by a mass.</span>
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In your own words, explain the effects of time dilation.
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So we want to explain the effects of time dilation. In theory of relativity time dilation is the difference of elapsed time between two events when measured by two observers who are moving relatively to each other. A clock of an observer that is standing still in an inertial frame of reference is going to measure a different time of an event than the clock of an observer that is moving with some velocity with respect to the inertial reference frame that is not moving. In a nutshell, the moving clock is ticking slower than the clock that is standing still.  
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Pls helpp!! Write a fictional story that takes place in a world without gravity.
kirza4 [7]

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Explanation:

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3 years ago
Linear Thermal Expansion (in one dimension)
Leokris [45]

Answer:

1) \Delta L= 0.612\ m

2) a. \Delta V_G=0.57\ L

   b. \Delta V_S=0.021\ L

   c. V_0=0.549\ L

Explanation:

1)

  • given initial length, L=1275\ m
  • initial temperature, T_i=-15^{\circ}C
  • final temperature, T_f=25^{\circ}C
  • coefficient of linear expansion, \alpha=12\times 10^{-6}\ ^{\circ}C^{-1}

<u>∴Change in temperature:</u>

\Delta T=T_f-T_i

\Delta T=25-(-15)

  • \Delta T=40^{\circ}C

We have the equation for change in length as:

\Delta L= L.\alpha. \Delta T

\Delta L= 1275\times 12\times 10^{-6}\times 40

\Delta L= 0.612\ m

2)

Given relation:

\Delta V=V.\beta.\Delta T

where:

\Delta V= change in volume

V= initial volume

\Delta T=change in temperature

  • initial volume of tank, V_{Si}=60\ L
  • initial volume of gasoline, V_{Gi}=60\ L
  • initial temperature of steel tank, T_{Si}=15^{\circ}C
  • initial temperature of gasoline, T_{Gi}=15^{\circ}C
  • coefficients of volumetric expansion for gasoline, \beta_G=950\times 10^{-6}\ ^{\circ}C
  • coefficients of volumetric expansion for gasoline, \beta_S=35\times 10^{-6}\ ^{\circ}C

a)

final temperature of gasoline, T_{Gf}=25^{\circ}C

∴Change in temperature of gasoline,

\Delta T_G=T_{Gf}-T_{Gi}

\Delta T_G=25-15

\Delta T_G=10^{\circ}C

Now,

\Delta V_G= V_G.\beta_G.\Delta T_G

\Delta V_G=60\times 950\times 10^{-6}\times 10

\Delta V_G=0.57\ L

b)

final temperature of tank, T_{Sf}=25^{\circ}C

∴Change in temperature of tank,

\Delta T_S=T_{Sf}-T_{Si}

\Delta T_S=25-15

\Delta T_S=10^{\circ}C

Now,

\Delta V_S= V_S.\beta_S.\Delta T_S

\Delta V_S=60\times 35\times 10^{-6}\times 10

\Delta V_S=0.021\ L

c)

Quantity of gasoline spilled after the given temperature change:

V_0=\Delta V_G-\Delta V_S

V_0=0.57-0.021

V_0=0.549\ L

8 0
3 years ago
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Answer:

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• There are four prism types;

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2 years ago
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