Answer:
C. AgNO3 + LICI - AgCl + LINO3
Explanation:
Here the chemical equation for double displacement reaction is
AgNO3 + LICI - AgCl + LINO3
The reaction in which two compounds react together to form two other compounds by mutual exchange of their ions is called double displacement reaction.
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Answer:
S(metal) = 0.66J/g°C
Explanation:
We can find specific heat of a material, S, using the equation:
q = m*S*ΔT
<em>Where q is change in heat, m is the mass of the substance, S specific heat and ΔT change in temperature.</em>
The heat given by the metal is equal to the heat that water absorbs, that is:
m(Metal)*S(metal)*ΔT(Metal) = m(Water)*S(water)*ΔT(water)
<em>Where:</em>
m(Metal) = 76.0g
S(metal) = ?
ΔT(Metal) = 96.0°C-31.0°C = 65.0°C
m(Water) = 120.0g
S(water) = 4.184J/g°C
ΔT(water) = 31.0°C-24.5°C = 6.5°C
Replacing:
76.0g*S(metal)*65.0°C = 120.0g*4.184J/g°C*6.5°C
S(metal) = 0.66J/g°C
<em />
The law of conservation applies because the energy is not been created or destroyed. The energy that the metal gives is absorbed by the water.
Answer:
NiS insoluble
Mg₃(PO₄)₂ insoluble
Li₂CO₃ soluble
NH₄Cl soluble
C₁₂H₂₂O₁₁ molecules
Explanation:
<em>Predict whether the following compounds are soluble or insoluble in water.</em>
Based on the solubility rules we can say:
- NiS: Sulfides of transition metals are highly insoluble.
- Mg₃(PO₄)₂: All phosphates (except those with metals of Group 1) are insoluble so Mg₃(PO₄)₂ is insoluble.
- Li₂CO₃: all salts of metals of Group 1 are soluble so Li₂CO₃ is soluble.
- NH₄Cl: all salts of ammonium are soluble so NH₄Cl is soluble.
<em>Which of the following best describes the solute in an aqueous solution of sucrose or C₁₂H₂₂O₁₁(aq)?</em>
Sucrose is a molecular compound in which atoms are linked through covalent bonds. Thus, it does not ionize in water (is a non-electrolyte) and when it dissolves it exists as C₁₂H₂₂O₁₁ molecules.
You get a tub of warm water and tip the warm water into the cold water
Answer:
The answer to your question is n = 5, l = 2, m can be -2, -1, 0, 1 or 2
Explanation:
Data
orbital = 5d
values of n, l, m
Process
1.- Determine the value of n
n is the coefficient of the orbital, in this problem n = 5
2.- Determine the value of l
l takes values depending in the sublevel of energy,
if the sublevel is s then l = 0
p l = 1
d l = 2
f l = 3
For this problem l = 2
3.- Determine the value of m
when l = 2, m takes values of -2, - 1, 0, 1 or 2
