Answer;
= 90600 m/s...
Explanation;
velocity of ball = 96 mi/hr = 42.916 m/s...
velocity of bat = -56mi/hr = -25.034m/s.. ( note the negativity here..)
time = 0.75 millisec = 0.75 * 10^-3 sec
acceleration = (velball - velbat) / time
= (42.916 - (-25.034)) / (0.75 * 10^-3)
=90600 m/s
Answer:
Index of refraction=Angle of incidence/Angle of refraction
=5/2.1
=2.38
Answer:
D. both have electrons that orbit the atomic nucleus in a simaler way
Explanation:
the bohrs model electrons orbit in a circular pattern were as the modern atomic model orbit in every which way
Answer:
The capacitance per unit length is ![5.06\times10^{-11}\ F/m](https://tex.z-dn.net/?f=5.06%5Ctimes10%5E%7B-11%7D%5C%20F%2Fm)
(b) is correct option.
Explanation:
Given that,
Radius a= 2.50 mm
Radius b=7.50 mm
Dielectric constant = 3.68
Potential difference = 120 V
We need to calculate charge per length for the capacitance
Using formula of charge per length
![\lambda=\dfrac{4\pi\epsilon_{0}\Delta V}{2 ln(\dfrac{r_{2}}{r_{1}})}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7B4%5Cpi%5Cepsilon_%7B0%7D%5CDelta%20V%7D%7B2%20ln%28%5Cdfrac%7Br_%7B2%7D%7D%7Br_%7B1%7D%7D%29%7D)
Put the value into the formula
![\lambda=\dfrac{120}{9\times10^{9}\times2 ln(\dfrac{7.50\times10^{-3}}{2.50\times10^{-3}})}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7B120%7D%7B9%5Ctimes10%5E%7B9%7D%5Ctimes2%20ln%28%5Cdfrac%7B7.50%5Ctimes10%5E%7B-3%7D%7D%7B2.50%5Ctimes10%5E%7B-3%7D%7D%29%7D)
![\lambda=6.068\times10^{-9}\ C/m](https://tex.z-dn.net/?f=%5Clambda%3D6.068%5Ctimes10%5E%7B-9%7D%5C%20C%2Fm)
We know that,
![\lambda=\dfrac{Q}{L}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7BQ%7D%7BL%7D)
We need to calculate the capacitance per unit length
Using formula of capacitance per unit length
![C=\dfrac{\dfrac{Q}{L}}{\Delta V}](https://tex.z-dn.net/?f=C%3D%5Cdfrac%7B%5Cdfrac%7BQ%7D%7BL%7D%7D%7B%5CDelta%20V%7D)
![C=\dfrac{6.068\times10^{-9}}{120}](https://tex.z-dn.net/?f=C%3D%5Cdfrac%7B6.068%5Ctimes10%5E%7B-9%7D%7D%7B120%7D)
![C=5.06\times10^{-11}\ F/m](https://tex.z-dn.net/?f=C%3D5.06%5Ctimes10%5E%7B-11%7D%5C%20F%2Fm)
Hence, The capacitance per unit length is ![5.06\times10^{-11}\ F/m](https://tex.z-dn.net/?f=5.06%5Ctimes10%5E%7B-11%7D%5C%20F%2Fm)
Answer:
245.45km in a direction 21.45° west of north from city A
Explanation:
Let's place the origin of a coordinate system at city A.
The final position of the airplane is given by:
rf = ra + rb + rc where ra, rb and rc are the vectors of the relative displacements the airplane has made. If we separate this equation into its x and y coordinates:
rfX = raX+ rbX + rcX = 175*cos(30)-150*sin(20)-190 = -89.75km
rfY = raY + rbY + rcT = 175*sin(30)+150*cos(20) = 228.45km
The module of this position is:
![rf = \sqrt{rfX^2+rfY^2} = 245.45km](https://tex.z-dn.net/?f=rf%20%3D%20%5Csqrt%7BrfX%5E2%2BrfY%5E2%7D%20%3D%20245.45km)
And the angle measure from the y-axis is:
![\alpha =atan(rfX/rfY) = 21.45\°](https://tex.z-dn.net/?f=%5Calpha%20%3Datan%28rfX%2FrfY%29%20%3D%2021.45%5C%C2%B0)
So the answer is 245.45km in a direction 21.45° west of north from city A