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Darya [45]
3 years ago
10

A temperature reading of zero on the Celsius scale is equal to absolute zero.

Physics
2 answers:
GrogVix [38]3 years ago
8 0
No, that's false.  'Zero' on the Celsius scale
is 273 on the absolute scale.
zhannawk [14.2K]3 years ago
5 0
False.

Absolute zero is actually 0 Kelvin.

Absolute zero is = -273°C, and not 0°C.

0 k = -273°C<span />
You might be interested in
Define pressure in short
Makovka662 [10]

Answer:

hope it helps......

Explanation:

Pressure, in the physical sciences, the perpendicular force per unit area, or the stress at a point within a confined fluid.

7 0
3 years ago
If a diver displace water with a weight of 500N what is the upthrust on the diver?​
ki77a [65]

Answer:

500 N

Explanation:

Natural bouyency will keep the diver in the same place, no matter what the mass of gfs. This means if the diver is displacing with a weight of 500 N, the upthrust will also be 500 N.

3 0
2 years ago
A point charge (–5.0 µC) is placed on the x axis at x = 4.0 cm, and a second charge (+5.0 µC) is placed on the x axis at x = –4.
AveGali [126]

Answer:

The magnitude of electric force is  7.2\times10^{-3} N

Explanation:

Coulomb's Law:

The force of attraction or repletion is

  • directly proportional to the products of charges i.e F\propto q_1q_2
  • inversely proportional to the square of distance i.e F\propto \frac{1}{r^2}

\therefore F\propto \frac{q_1q_2}{r^2}

\Rightarrow F=k \frac{q_1q_2}{r^2}    [ k is proportional constant=9×10⁹N m²/C²]

There are two types of force applied on Q=+2.5 μC=2.5×10⁻⁶ C

Let F₁ force be applied on Q =+2.5 μC by q₁= -5.0 μC = - 5.0×10⁻⁶ C

and F₂ force  be applied on Q=+2.5 μC by q₂= 5.0 μC= 5.0×10⁻⁶ C

Since the magnitude of F₁ and F₂ are same. Therefore their y component cancel.

If we draw a line from q₁ to Q .

The it forms a triangle whose base = 4.0 cm and altitude =3.0 cm.

Let hypotenuse = r

Therefore, r=\sqrt{altitude^2+base^2} =\sqrt{3^2+4^2} =5

we know,

cos \theta = \frac{base }{hypotenuse}

\Rightarrow cos \theta = \frac{4 }{r}

Total force F_Q = 2.F_1 cos\theta \hat{i}

                         =2k\frac{Qq_1}{r^2} cos\theta \hat i

                         =2\ \frac{9\times1 0^9\times2.5 \times 5\times 10^{-12}}{r^2} \frac{4}{r} \hat i

                         =8\ \frac{9\times10^9\times2.5 \times 5\times 10^{-12}}{5^3} \hat i     [ r=5]

                         =7.2\times10^{-3}\hat i   N

The magnitude of electric force is  7.2\times10^{-3} N

                         

3 0
3 years ago
Dont know whether its b or c. (cuz for sure it transports energy)
masha68 [24]

Sound waves are a type of classical waves and so they transport only energy without transporting matter through the medium.

6 0
3 years ago
3000 centímetros cúbicos de un gas ideal a 80°C se expande hasta un volumen de 1000 cm³ a presión constante. ¿Cuál es la tempera
mixer [17]

Responder:

117,6 K

Explicación:

Dado :

V1 = 3000 cm³

T1 = 80 ° C = 273 + 80 = 353 K

V2 = 1000 cm³

T2 =?

La ley de Fromm Charles;

3000/353 = 1000 / T2

3000T2 = 353 * 1000

T2 = 353000/3000

T2 = 117. 67 k

4 0
2 years ago
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