The Silence of the Lambs ends when Hannibal Lecter, from a payphone in the tropics, congratulates FBI Academy graduate Clarice Starling and gently warns her not to hunt him, ending the call by saying he had to go because he was having a friend for dinner, as he watched his hospital tormenter, Dr. Chilton, disembark from a plane. While that nervous laugh allowed movie goers to summon the courage to leave the theater and run to their cars, the original ending scripted by Tally gave no such quarter. When Lecter speaks to Starling, he compliments her outfit, which makes her realize he had watched from a distance. In the original ending, Lecter is cutting orange segments with a small paring knife, while he speaks to Clarice. As he hangs up the phone, the camera shot widens. We discover that he”s at a desk in a book lined office. There is the body of a bodyguard on the floor, and then we see Lecter is not alone. Chilton is trussed up in a chair across from him, the same method of restraints the doctor used on Lecter earlier in the movie. Lecter rises, slowly, a dreamy gleam in his eye, as he approaches his terrified victim, paring knife in hand. “Shall we begin?”
Acceleration is any change in speed or direction of motion.
The dimension of speed is [length/time],
so a change is [length/time²].
Popular units include [meter/second²] and [feet/second²] .
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Direction almost always boils down to an angle, (which technically
has no dimensions), so a change in direction is [angle/time] .
Popular units include [radian/second] and [degree/second] .
Answer:
The depth of the well, s = 54.66 m
Given:
time, t = 3.5 s
speed of sound in air, v = 343 m/s
Solution:
By using second equation of motion for the distance traveled by the stone when dropped into a well:
Since, the stone is dropped, its initial velocity, u = 0 m/s
and acceleration is due to gravity only, the above eqn can be written as:
(1)
Now, when the sound inside the well travels back, the distance covered,s is given by:
(2)
Now, total time taken by the sound to travel:
t = t' + t''
t'' = 3.5 - t' (3)
Using eqn (2) and (3):
s = 343(3.5 - t') (4)
from eqn (1) and (4):
Solving the above quadratic eqn:
t' = 3.34 s
Now, substituting t' = 3.34 s in eqn (2)
s = 54.66 m
Answer:
91.3°F
Explanation:
Let T be the temperature of the thermometer at any time
T∞ be the temperature of the room = 70°F
T₀ be the initial temperature of the thermometer = 212°F
And m, c, h are all constants from the cooling law relation
From Newton's law of cooling
Rate of Heat loss by the cake = Rate of Heat gain by the environment
- mc (d/dt)(T - T∞) = h (T - T∞)
(d/dt) (T - T∞) = dT/dt (Because T∞ is a constant)
dT/dt = (-h/mc) (T - T∞)
Let (h/mc) be k
dT/(T - T∞) = -kdt
Integrating the left hand side from T₀ to T and the right hand side from 0 to t
In [(T - T∞)/(T₀ - T∞)] = -kt
(T - T∞)/(T₀ - T∞) = e⁻ᵏᵗ
(T - T∞) = (T₀ - T∞)e⁻ᵏᵗ
Inserting the known variables
(T - 70) = (212 - 70)e⁻ᵏᵗ
(T - 70) = 142 e⁻ᵏᵗ
At t = 2 minute, T = 125°F
125 - 70 = 142 e⁻ᵏᵗ
55/142 = e⁻ᵏᵗ
- kt = In (55/142) = In (0.3873)
- k(2) = - 0.9485
k = 0.4742 /min
At time t = 4 mins
kt = 0.4742 × 4 = 1.897
(T - 70) = 142 e⁻ᵏᵗ
e^(-1.897) = 0.15
T - 70 = 142 × 0.15 = 21.3
T = 91.3°F
