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2 years ago

11

Students are measuring the length of time it takes for soda to go flat at three different temperatures. Which type of graph shou

ld the students use to display their data?

1 answer:

maksim [4K]2 years ago

4 0

Bar Graph. It shows time very well.

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What substances were found in the innermost regions (within about the inner 0.3 au) of the solar system before planets began to

coldgirl [10]

The answer would be Rocks, metals, hydrogen compounds, hydrogen and helium, all in gaseous form.

5 0

2 years ago

What is the maximum pressure at which solid CO2 (dry ice) can be converted into CO2 gas without melting?

max2010maxim [7]

Answer:

Explanation:

The triple point of carbon dioxide is 5.11 atmosphere at -56.6 degree celsius . At pressure greater than 5.11 , solid carbon dioxide liquefies , as it is warmed. At pressure lesser than 5.11 atmosphere , it will go into gaseous state without liquefying . Excessive pressure helps liquification process.

So maximum pressure required is 5.11 atmosphere. Beyond this pressure , solid CO2 will liquify.

3 0

3 years ago

Would convection work if there were no<br> gravity? Why<br> or<br> why not

Pavel [41]

Answer:

no

Explanation:

Because gravity is necessary for density differences to arise, convection wouldn't happen in a zero-gravity environment such as space.

4 0

2 years ago

Read 2 more answers

Hi! please help me identify the IUPAC name for the structures

Snowcat [4.5K]

The IUPAC names of the organic compounds would be as follows:

1. Methanol or 1-Methanol

2. Propan-2-ol or 2-Propanol

3. 2-MethylButane

4. 1-Hexanol

5. 1-Heptanol

<h3>Naming organic compounds</h3>

In the naming of organic compounds, some fundamental rules come into practice. Some of these rules include:

The longest carbon chain, otherwise known as the parent chain, is considered.
The substituents must be identified
The parent chain should be named such that the substituents are located on the lowest-numbered carbons. Repeated substituents are named accordingly.
Different substituents are named alphabetically and substituents with lower alphabets are considered for the lowest-numbered carbons.

Following these rules and more, the name of the organic compounds whose structures are shown in the image would be as follows:

Methanol or 1-Methanol
Propan-2-ol or 2-Propanol
2-MethylButane
1-Hexanol
1-Heptanol

More on IUPAC naming can be found here: brainly.com/question/16631447

#SPJ1

7 0

1 year ago

Iron(III) oxide and hydrogen react to form iron and water, like this: Fe_2O_3(s) + 3H_2(g) rightarrow 2Fe(s) + 3H_2O(g) At a cer

Sergeeva-Olga [200]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The equilibrium constant is $K_c= 2.8*10^{-4}$

Explanation:

From the question we are told that

The chemical reaction equation is

$Fe_{2} O_{3}_{(s)} + 3H_{2}_{(g)} -----> 2Fe_{(s)} + 3H_{2} O_{(g)}$

The voume of the misture is $V_m = 5.4L$

The molar mass of $Fe_{2} O_{3}_{(s)}$ is a constant with value of $M_{Fe_{2} O_{3}_{(s)} } = 160g/mol$

The molar mass of $H_{2}_{(g)}$ is a constant with value of $H_2 = 2g/mol$

The molar mass of $H_{2}O$ is a constant with value of $H_2O = 18g/mol$

Generally the number of moles is mathematically given as

$No \ of \ moles \ = \frac{mass}{molar\ mass}$

For $Fe_{2} O_{3}_{(s)}$

$No \ of\ moles = \frac{3.54}{160}$

$= 0.022125 \ mols$

For $H_{2}$

$No \ of\ moles = \frac{3.63}{2}$

$= 1.815 \ mols$

For $H_{2}O$

$No \ of\ moles = \frac{2.13}{18}$

$= 0.12 \ mols$

Generally the concentration of a compound is mathematicallyrepresented as

$Concentration = \frac{No \ of \ moles }{Volume }$

For $Fe_{2} O_{3}_{(s)}$

$Concentration[Fe_2 O_3] = \frac{0.222125}{5.4}$

$= 4.10*10^{-3}M$

For $H_{2}$

$Concentration[H_2] = \frac{1.815}{5.4}$

$= 0.336M$

For $H_{2}O$

$Concentration [H_2O] = \frac{0.12}{5.4}$

$= 0.022M$

The equilibrium constant is mathematically represented as

$K_c = \frac{[concentration \ of \ product]}{[concentration \ of \ reactant ]}$

Considering $H_2O \ for \ product$

And $H_2 \ for \ reactant$

At equilibrium the

$K_c = \frac{0.022}{0.336}$

$K_c= 2.8*10^{-4}$

3 0

2 years ago