Photochemical chlorination of 1,2−dibromoethane gives a mixture of two stereoisomers of c2h3br2cl. draw the structure of one of
the products
1 answer:
<em>See the structure at the bottom-left corner of the sketch attached.</em>
<h3>Explanation</h3>Replacing an H atom with a Cl atom in a 1,2-dibromoethane molecule produces a molecule of C₂H₃Br₂Cl. Its structural formula is show in the top-left corner of the sketch attached.
The molecule contains no double or triple bonds. It has no E/Z isomers. The two stereoisomers can only be enantiomers. A red asterisk * is placed next to the only <em>chiral</em> carbon in this molecule.
That carbon atom is connected to
- one H atom,
- one Cl atom,
- one Br atom, and
- the alkyl group CH₂Br.
The two isomers are <em>mirror images </em>about this carbon atom. Indicate how the four groups are arranged in space using the wedge and dash notation.
- Solid lines refer to chemical bonds in the plane of the paper.
- Wedges refer to bonds pointing out of the page towards you.
- Dashes refer to bonds pointing into the page away from you.
The last row of this sketch shows the structure of both isomers. The question is asking for only one. Showing either of them should work.
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Explanation:
the pH of the solution defined as negatuve logarithm of ion concentration.
1. Hydrogen ion concentration when pH of the solution is 11.
..(1)
At pH = 11, the concentration of ions is
.
2. Hydrogen ion concentration when the pH of the solution is 6.
..(2)
At pH = 6, the concentration of ions is
.
3. On dividing (1) by (2).
The ratio of hydrogen ions in solution of pH equal to 11 to the solution of pH equal to 6 is .
4. Difference between the ions at both pH:
This means that Hydrogen ions in a solution at pH = 7 has ions fewer than in a solution at a pH = 6